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Bunuel
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the answer is B

the circle will form tringle that have absic =8 and hight= 3

so the area is 1/2*8*3=12
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Center of the circle =(5,3) & Radius = 5; circle touches y axis at (0,3), and X axis at (1,0) & (9,0) (with help of radius y intercept we can find x intercept using Pythagorean theorem ).
Therefore Area of triangle = 3*8 /2 = 12
Therefore ans is B

Thanks
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Quote:
What is the area of the triangle formed by these three intercepts

Shouldn't this be rephrased as "What is the area of the triangle formed by the x-inercepts and the centre?
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StrikerT
Quote:
What is the area of the triangle formed by these three intercepts

Shouldn't this be rephrased as "What is the area of the triangle formed by the x-inercepts and the centre?

No, because question asks about about area of triangle with vertexes at coordinates: (0, 3), (1, 0) and (9, 0)

On the picture we see height of triangle that drew from point (5, 3) because this is height and doesn't matter from which point we will draw it: from (0, 3) or from (5, 3) it's still height of this triangle.
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Harley1980
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Quote:
What is the area of the triangle formed by these three intercepts

Shouldn't this be rephrased as "What is the area of the triangle formed by the x-inercepts and the centre?

No, because question asks about about area of triangle with vertexes at coordinates: (0, 3), (1, 0) and (9, 0)

On the picture we see height of triangle that drew from point (5, 3) because this is height and doesn't matter from which point we will draw it: from (0, 3) or from (5, 3) it's still height of this triangle.

Ah. How can I miss that. :(
Thanks.
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Bunuel
Point W = (5, 3). Circle J has a center at point W and radius of r = 5. This circle intersects the y-axis at one intercept and the x-axis at two intercepts. What is the area of the triangle formed by these three intercepts?

(A) 7.5
(B) 12
(C) 15
(D) 24
(E) 30

Kudos for a correct solution.

At Y=0 ,
(x-5)^2 + 9 = 25 ; X-5 = +-4; X=9,1
At X=0
25+(Y-3)^2 = 25 ; Y=3.

area of triangle = 1/2 * 3 * (9-1) = 12 .
answer B.
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Circle cuts at (0,3), (1,0) and (9,0). Area of bigger triangle with points (0,3), (0,0) and (9,0) is 27/2.
Area of smaller triangle with points (0,3), (0,0) and (1,0) is 3/2.
Therefore, 27/2- 3/2 = 24/2 = 12.
Ans b

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Well, that took a solid 7 minutes trying to figure out what the x-intercepts are for this.

First, if the centre is at W(5,3) and the radius is at 5, then one of the vertices is at (0,3). Therefore the height is 3: h = 3.

Next, figure out what the x-intercepts are.

d = √(x2 - x1)^2 + (y2 - y1)^2
5 = √(5 - x1)^2 + (3-0)^2
25 = (5-x1)^2 + 9
16 = (5-x1)^2
4 = | 5 - x1|
x1 = 1, 9

So, the x intercepts are (1,0) and (9,0).

Therefore, the base of the triangle is 9 - 1 = 8.

A = 8 x 3 /2 = 12.

B. (Upon looking at the other answers, is my approach wrong?)
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