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Subanta
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this threw m off.....but
assuming the last quotient to be 1, i get:
8 x 1 + 5 = 13
7 x 13 +4 = 95
6 x 95 +2 = 572
5 x 572 + 1 = 2861

now i do the reverse division and get remainders: 5, 0, 3, 3 for a total of 11
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Subanta
When a natural number N is successively divided by 5,6,7,8 the remainders are 1,2,4,5. What will be the sum of the remainders if the order of the division is reversed?

A: 16
B: 14
C: 12
D: 11
E: 9
­For successive divisions, we need to calculate from the back-end.
The family of numbers which when divided by 8 gives the remainder as 5=8s+5.
Similarly, we get 56s+39, 336s+236 and 1680s+1181.
Now, 1680 is divisible by 5,6,7,8 so let us divide 1181 with 8,7,6,5 (reverse order as asked in question).
1181/8 gives rem=5 and quo=147.
147/7 gives rem=0 and quo=21.
21/6 gives rem=3 and quo=3.
3/5 gives rem=3 and quo=0.
Therefore, 5+0+3+3=11. Option (D) is correct.
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