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24 Jan 2016, 06:27
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
56% (01:21) correct
44%
(01:25)
wrong
based on 95
sessions
History
Date
Time
Result
Not Attempted Yet
Given that AB is tangent to the circle with center C, what is the length of the circle’s radius?
(1) AD = 4
(2) AC = 10
Attachment:
2016-01-24_1725.png [ 4.72 KiB | Viewed 6019 times ]
24 Jan 2016, 08:28
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Bunuel
two ways to do it..
1) if we extend the radius DC to intersect at circumference say at E..
then AB^2=AD*AE..
8^2=AD(2r+AD)..
there are two unknowns, value of AD or the radius is suff to answer..
2) Join BC..
ABC becomes a right angle triangle, whose sides are..
AB=8, BC=r, AC=r+AD..
so AC^2=AB^2+BC^2..
if we know r or AD we can again answer,,..
lets see the choices.
(1) AD = 4..
Suff
(2) AC = 10
Suff
ans D
24 Jan 2016, 11:39
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Bunuel
Since AB is tangent, <ABC is right angle.
In the Right angle triangle ABC, AB^2 + BC^2 = AC^2; we need to find BC^2
(1) AD = 4 => Given AD, we can certainly find BC, as (AD+DC)^2 + BC^2 = 8^2 & BC = DC;
(2) AC = 10 => Clearly , BC^2 = 10^2 + 8^2
Ans is D.
