Last visit was: 23 Apr 2026, 01:44 It is currently 23 Apr 2026, 01:44
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Ekland
Joined: 15 Oct 2015
Last visit: 30 Apr 2023
Posts: 355
Own Kudos:
878
 [23]
Given Kudos: 342
Concentration: Finance, Strategy
GPA: 3.93
WE:Account Management (Education)
2
Kudos
Add Kudos
21
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
KarishmaParmar
Joined: 15 Feb 2016
Last visit: 21 Jan 2017
Posts: 51
Own Kudos:
37
 [5]
Given Kudos: 28
GMAT 1: 710 Q48 V40
Products:
GMAT 1: 710 Q48 V40
Posts: 51
Kudos: 37
 [5]
5
Kudos
Add Kudos
Bookmarks
Bookmark this Post
General Discussion
User avatar
ENGRTOMBA2018
Joined: 20 Mar 2014
Last visit: 01 Dec 2021
Posts: 2,319
Own Kudos:
Given Kudos: 816
Concentration: Finance, Strategy
GMAT 1: 750 Q49 V44
GPA: 3.7
WE:Engineering (Aerospace and Defense)
Products:
GMAT 1: 750 Q49 V44
Posts: 2,319
Kudos: 3,889
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
iliavko
Joined: 08 Dec 2015
Last visit: 28 Apr 2019
Posts: 255
Own Kudos:
138
 [2]
Given Kudos: 36
GMAT 1: 600 Q44 V27
Products:
GMAT 1: 600 Q44 V27
Posts: 255
Kudos: 138
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
What is being tested in this question?

Is there a fast way to realize that 17 times 23 is 391? How can you do it fast? Otherwise I don't see what's the point of this question.

Thanks!
User avatar
ENGRTOMBA2018
Joined: 20 Mar 2014
Last visit: 01 Dec 2021
Posts: 2,319
Own Kudos:
3,889
 [4]
Given Kudos: 816
Concentration: Finance, Strategy
GMAT 1: 750 Q49 V44
GPA: 3.7
WE:Engineering (Aerospace and Defense)
Products:
GMAT 1: 750 Q49 V44
Posts: 2,319
Kudos: 3,889
 [4]
3
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
iliavko
What is being tested in this question?

Is there a fast way to realize that 17 times 23 is 391? How can you do it fast? Otherwise I don't see what's the point of this question.

Thanks!

Realize that 17*23= (20-3)*(20+3) = 20^2-3^2= 400-9 = 391.

I used the relation that (a-b)(a+b)= a^2-b^2

Posted from my mobile device
User avatar
iliavko
Joined: 08 Dec 2015
Last visit: 28 Apr 2019
Posts: 255
Own Kudos:
138
 [2]
Given Kudos: 36
GMAT 1: 600 Q44 V27
Products:
GMAT 1: 600 Q44 V27
Posts: 255
Kudos: 138
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Nice one!.. Didn't notice the difference of squares!

Good job! thank you :)
User avatar
GMATGuruNY
Joined: 04 Aug 2010
Last visit: 02 Apr 2026
Posts: 1,347
Own Kudos:
Given Kudos: 9
Schools:Dartmouth College
Expert
Expert reply
Posts: 1,347
Kudos: 3,905
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Ekland
Is x < - 20 ?

(1) x^2 + 40x + 391 = 0

(2) x^2 = 529

Statement 2:
Since \(20^2=400\) and \(30^2 = 900\), the positive root must be between 20 and 30.
For the units of \(x^2\) to be 9, x must have a units digit of 3 or 7.
Since 529 is much closer to 400 than to 900, the positive root must be 23, implying that the negative root is -23.
If x=23, the answer to the question stem is NO.
If x=-23, the answer to the question stem is YES.
INSUFFICIENT.

RULE:
For any DS problem, there must be at least one case that satisfies BOTH statements.

Statement 1:
\(x^2 + 40x + 391 = (x+a)(x+b)\), where \(a+b = 40\).
In accordance with the rule above, one of the roots of this quadratic must be 23 or -23.
Thus, the two factors must look as follows:
\((x+23)(x+b)\)
Since 23+b = 40, b=17, with the result that the second factor is (x+17):
\((x+23)(x+17)\)
Thus, x=-23 or x=-17.
If x=-17, the answer to the question stem is NO.
If x=-23, the answer to the question stem is YES.
INSUFFICIENT.

Statements combined:
Only x=-23 satisfies both statements.
Thus, the answer to the question stem is YES.
SUFFICIENT.

User avatar
Basshead
Joined: 09 Jan 2020
Last visit: 07 Feb 2024
Posts: 907
Own Kudos:
Given Kudos: 431
Location: United States
Posts: 907
Kudos: 323
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Ekland
Is x < - 20 ?

(1) x^2 + 40x + 391 = 0

(2) x^2 = 529

(1) \(x^2 + 40x + 391 = 0\)
\((x+17)(x+23)\)

\(x = -17, -23\); INSUFFICIENT.

(2) \(X^2 = 529\)
x can be positive or negative; INSUFFICIENT.

(1&2) Combined, \(x = -23\). SUFFICIENT.

Answer is C.
User avatar
TestPrepUnlimited
Joined: 17 Sep 2014
Last visit: 30 Jun 2022
Posts: 1,223
Own Kudos:
Given Kudos: 6
Location: United States
GMAT 1: 780 Q51 V45
GRE 1: Q170 V167
Expert
Expert reply
GMAT 1: 780 Q51 V45
GRE 1: Q170 V167
Posts: 1,223
Kudos: 1,138
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Ekland
Is x < - 20 ?

(1) x^2 + 40x + 391 = 0

(2) x^2 = 529

We don't have to factor anything to solve this question logically, we only need to know \(x^2 = 400\) as a reference.

Statement 1:

There are two negative solutions because all signs are positive. -40 is the sum of the roots, half of that is -20. The solutions are not both -20, thus one of the solutions must be bigger than -20 and one must be less than -20. We would have a "no" and "yes" answer so insufficient.

Statement 2:

The value on the right is greater than 400, so we know the magnitude of x is greater than 20. We get one solution less than -20 and one greater than 20, insufficient.

Combined:

Statement 1 has two negative solutions, statement 2 has one negative one positive, combined there is only one possible value for x which is negative. Sufficient.

Ans: C
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,960
Own Kudos:
Posts: 38,960
Kudos: 1,117
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109763 posts
498 posts
212 posts