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Is x < - 20 ?

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Is x < - 20 ? [#permalink]

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New post 15 Feb 2016, 08:20
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Question Stats:

69% (01:10) correct 31% (01:14) wrong based on 117 sessions

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Is x < - 20 ?

(1) x^2 + 40x + 391 = 0

(2) x^2 = 529
[Reveal] Spoiler: OA

Last edited by Bunuel on 15 Feb 2016, 08:23, edited 1 time in total.
Edited the question.

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Re: Is x < - 20 ? [#permalink]

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New post 15 Feb 2016, 09:34
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Nez wrote:
Is x < - 20 ?

(1) x^2 + 40x + 391 = 0

(2) x^2 = 529



From statement 1
x^2 +23x+17x+391 =0
(x+23) (x+17) = 0
x= -23 , -17

From statement 2
x= +23, -23

From Both
x= -23

Hence C

Was it this simple? Did I miss something? Any reason it is 700 level?
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Re: Is x < - 20 ? [#permalink]

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New post 15 Feb 2016, 09:36
KarishmaParmar wrote:
Nez wrote:
Is x < - 20 ?

(1) x^2 + 40x + 391 = 0

(2) x^2 = 529



From statement 1
x^2 +23x+17x+391 =0
(x+23) (x+17) = 0
x= -23 , -17

From statement 2
x= +23, -23

From Both
x= -23

Hence C

Was it this simple? Did I miss something? Any reason it is 700 level?


Thanks. Updated the tag. Your solution is fine.
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Re: Is x < - 20 ? [#permalink]

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New post 24 Jun 2016, 03:50
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What is being tested in this question?

Is there a fast way to realize that 17 times 23 is 391? How can you do it fast? Otherwise I don't see what's the point of this question.

Thanks!

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Re: Is x < - 20 ? [#permalink]

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New post 24 Jun 2016, 04:15
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iliavko wrote:
What is being tested in this question?

Is there a fast way to realize that 17 times 23 is 391? How can you do it fast? Otherwise I don't see what's the point of this question.

Thanks!


Realize that 17*23= (20-3)*(20+3) = 20^2-3^2= 400-9 = 391.

I used the relation that (a-b)(a+b)= a^2-b^2

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Re: Is x < - 20 ? [#permalink]

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New post 24 Jun 2016, 04:29
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Nice one!.. Didn't notice the difference of squares!

Good job! thank you :)

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Re: Is x < - 20 ? [#permalink]

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Re: Is x < - 20 ?   [#permalink] 31 Aug 2017, 21:34
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