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21 Apr 2017, 07:51
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Difficulty:
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Question Stats:
65% (01:22) correct
35%
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wrong
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The function f is defined by \(f(x)=2^{(x−1)}−5\). If \(f(x)=63\), then the value of x must be:
A. Less than 5
B. Between 5 and 6
C. Between 6 and 7
D. Between 7 and 8
E. Greater than 8
A. Less than 5
B. Between 5 and 6
C. Between 6 and 7
D. Between 7 and 8
E. Greater than 8
sashiim20
Joined: 04 Dec 2015
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Location: India
Concentration: Technology, Strategy
Schools: ISB '19 IIMB IIMA XLRI HEC Sept19 intake Rotman '21 NUS '21 NTU '20 Trinity MBA '20 Bocconi '21 Smurfit "21
WE:Information Technology (Consulting)
Schools: ISB '19 IIMB IIMA XLRI HEC Sept19 intake Rotman '21 NUS '21 NTU '20 Trinity MBA '20 Bocconi '21 Smurfit "21
Posts: 608
08 May 2017, 23:53
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The function f is defined by f(x)=\(2^{(x−1)}\)−5. If f(x)=63, then the value of x must be:
From above equation, \(2^{(x−1)}\)−5 = 63
\(2^{(x−1)}\) = 63+5 = 68
\(2^x\) / 2 = 68
\(2^x\) = 68 x 2 = 136
Since 2^7 = 128 and 2^8 = 256... Value of x must be between 7 and 8. Answer D...
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From above equation, \(2^{(x−1)}\)−5 = 63
\(2^{(x−1)}\) = 63+5 = 68
\(2^x\) / 2 = 68
\(2^x\) = 68 x 2 = 136
Since 2^7 = 128 and 2^8 = 256... Value of x must be between 7 and 8. Answer D...
_________________
Kindly press "+1 Kudos" to appreciate
General Discussion
21 Apr 2017, 08:23
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f(x)=63
2^(x-1) -5 =f(x)
2^(x-1) -5 = 63
2^(x-1) = 68
x-1 should be between 6 and 7 so that 2^(x-1) will lie between 64 and 128
So x should lie between 7 and 8
2^(x-1) -5 =f(x)
2^(x-1) -5 = 63
2^(x-1) = 68
x-1 should be between 6 and 7 so that 2^(x-1) will lie between 64 and 128
So x should lie between 7 and 8
