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02 Sep 2017, 13:29
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49%
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In each of the first five years of a bachelor degree program of four years, the intake is supposed to increase by 1/5th of the intake in the inception year. If the total number of enrollments after five years is S and no student failed or dropped out over these five years, how many students were studying in the four years of the degree program towards the end of the fifth year?
A. S
B. \(\frac{6S}{7}\)
C. \(\frac{5.2S}{7}\)
D. \(\frac{55}{7}\)
E. \(\frac{4S}{7}\)
Source : Experts Global
A. S
B. \(\frac{6S}{7}\)
C. \(\frac{5.2S}{7}\)
D. \(\frac{55}{7}\)
E. \(\frac{4S}{7}\)
Source : Experts Global
04 Sep 2017, 01:15
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Hi pclawong,
If we assume the intake for the first year to be x.
Since there is a increase of 20%(1/5th) of the intake in the inception year, the constant increase is .2x
Therefore, the intake for the second year is 1.2x.
Similarly the intake for the third year is 1.4x, for the fourth year is 1.6x, and for the fifth year is 1.8x
Now, we know that S = x+1.2x+1.4x+1.6x+1.8x = 7x
So at the end of the fifth year, only 4 year students remain having 6x students.
Hence the fraction is \(\frac{6S}{7}\)(Option B)
Please find the video explanation provided by Experts Global
If we assume the intake for the first year to be x.
Since there is a increase of 20%(1/5th) of the intake in the inception year, the constant increase is .2x
Therefore, the intake for the second year is 1.2x.
Similarly the intake for the third year is 1.4x, for the fourth year is 1.6x, and for the fifth year is 1.8x
Now, we know that S = x+1.2x+1.4x+1.6x+1.8x = 7x
So at the end of the fifth year, only 4 year students remain having 6x students.
Hence the fraction is \(\frac{6S}{7}\)(Option B)
Please find the video explanation provided by Experts Global
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