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19 Sep 2017, 04:05
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B
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Difficulty:
65%
(hard)
Question Stats:
53% (01:42) correct
47%
(01:39)
wrong
based on 198
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In which quadrant does the point P(x,y) lie?
(1) Point R(x, y+1) is in the second quadrant.
(2) Point Q(x+3, y) is in the third quadrant.
(1) Point R(x, y+1) is in the second quadrant.
(2) Point Q(x+3, y) is in the third quadrant.
19 Sep 2017, 04:21
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In which quadrant does the point P(x,y) lie?
(1) Point R(x, y+1) is in the second quadrant.
In the second quadrant, x-coordinate is negative and y-coordinate is positive. So, x < 0 and y + 1 > 0 (y > -1). y > -1, means that y could be negative as well as positive, thus P(x, y) could be P(negative, negative) = III quadrant as well as P(negative, positive) = II quadrant. Not sufficient.
(2) Point Q(x+3, y) is in the third quadrant.
In the third quadrant, both x and y coordinates are negative. So, x + 3 < 0 (x < -3) and y < 0. Since, x < -3, then it's negative, thus P(x, y) = P(negative, negative) = III quadrant. Sufficient.
Answer: B.
(1) Point R(x, y+1) is in the second quadrant.
In the second quadrant, x-coordinate is negative and y-coordinate is positive. So, x < 0 and y + 1 > 0 (y > -1). y > -1, means that y could be negative as well as positive, thus P(x, y) could be P(negative, negative) = III quadrant as well as P(negative, positive) = II quadrant. Not sufficient.
(2) Point Q(x+3, y) is in the third quadrant.
In the third quadrant, both x and y coordinates are negative. So, x + 3 < 0 (x < -3) and y < 0. Since, x < -3, then it's negative, thus P(x, y) = P(negative, negative) = III quadrant. Sufficient.
Answer: B.
General Discussion
19 Sep 2017, 04:34
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1) Point R(x, y+1) is in the second quadrant.
This states that x is negative.
but we clearly don't get any idea about y.
y can be positive as well as negative.
eg: x=-3 y=2 then R(x,y+1) in II quadrant.
x=-3, y= -0.5 then R(x,y+1) in II quadrant.
Statement I is insufficient.
(2) Point Q(x+3, y) is in the third quadrant.
this states that x+3 is negative and y is negative.
if x+3 is negative then x will be negative as well for all possible cases.
hence x is negative and y is negative; means point P will be in III quadrant.
Statement II is sufficient.
hence, Answer is B.
Kudos if it helps.
This states that x is negative.
but we clearly don't get any idea about y.
y can be positive as well as negative.
eg: x=-3 y=2 then R(x,y+1) in II quadrant.
x=-3, y= -0.5 then R(x,y+1) in II quadrant.
Statement I is insufficient.
(2) Point Q(x+3, y) is in the third quadrant.
this states that x+3 is negative and y is negative.
if x+3 is negative then x will be negative as well for all possible cases.
hence x is negative and y is negative; means point P will be in III quadrant.
Statement II is sufficient.
hence, Answer is B.
Kudos if it helps.
