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Let the percentage (profit or Loss) in each case be x%

Let the cost price be $C

Then , 1920 = C * \(\frac{(100 + x )}{100}\) (Profit of x%)
1280 = C * \(\frac{(100 - x)}{100}\) (Loss of x%)

Adding the two equations,

1920 + 1280 = 2C

C = 1600

Now, to make 25% profit,

Selling Price = 1600 *\(\frac{125}{100}\)

= 2000 Choice A
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Bunuel, could you please step in here? No explanation seems to do the trick sufficiently...

I'm confused!
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gota900
Bunuel, could you please step in here? No explanation seems to do the trick sufficiently...

I'm confused!

Here is an easy solution: https://gmatclub.com/forum/the-percenta ... l#p1941691 C there stands for the COST. Recall that both profit and loss are calculated on the cost of an item.
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varun4s
The percentage profit earned by selling an article for $1920 is equal in the percentage loss incurred by selling the same article for $1280. At what price should the article be sold to make 25% profit?

A) 2000
B) 2200
C) 2400
D) 2600
E) 2800


(1920-x)/x = (x-1280)/x

x= 1600

x-1600/1600 = 25/100

x = $2000 IMO A
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varun4s
The percentage profit earned by selling an article for $1920 is equal in the percentage loss incurred by selling the same article for $1280. At what price should the article be sold to make 25% profit?

A) 2000
B) 2200
C) 2400
D) 2600
E) 2800
CP is \(\frac{1920 + 1280}{2} = 1600\)

SP of the item at 25% profit is \(1600*\frac{5}{4} = 2000\), Answer must be (A)
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varun4s
The percentage profit earned by selling an article for $1920 is equal in the percentage loss incurred by selling the same article for $1280. At what price should the article be sold to make 25% profit?

A) 2000
B) 2200
C) 2400
D) 2600
E) 2800

Since we're told Loss % = Profit %; the CP should be somewhere in between Loss and Profit.
Hence 1920+1280/2 = CP
Therefore 1600 = CP
We need to find 25% profit
1600 x 125/100 is approximately 2000
Hence A
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