If a, b, c, d, e are consecutive positive integers such that a

Question

If a, b, c, d, e are consecutive positive integers such that ahttps://www.GMATinsight.com

CounterSniper · Answer

since a,b,c,d,e are consecutive positive integers

they can also be written as 
a,a+1,a+2,a+3,a+4,

average of Set (b, c, d, e) =  \frac{(4a+10)}{4} 
average of Set (a, b, c, d) =  \frac{(4a+6)}{4} 
difference =  \frac{(4a+10)}{4}  -  \frac{(4a+6)}{4}  =1
D

pranjal123 · Answer

Put 1,2,3,4,5 for a,b,c,d,e respectively and find the average for each set and then the difference of average. D Please +1 for kudos if you liked my post

ScottTargetTestPrep · Answer

We see that b = a + 1, c = a + 2, d = a + 3 and e = a + 4. The difference between the averages of the two given sets is:

(b + c + d + e)/4 - (a+ b + c + d)/4

(e - a)/4

(a + 4 - a)/4

4/4 = 1

Answer: D

gmat1393 · Answer

since they are consecutive, let a=a
=> b=a+1,c=a+2,d=a+3 and e = a+4

(b+c+d+e)/4 - (a+b+c+d)/4

=> e-a/4
=>a+4-a/4

= 1.

Option D is the answer.

ArjunJag1328 · Answer

a<b<c<d<e

They are in ascending order. So plug in values - {1<2<3<4<5)

b+c+d+e/4 = 2+3+4+5/4 = 14/4=7/2
a+b+c+d/4 = 1+2+3+4/4 = 10/4=5/2

Difference = 7/2-5/2 = 2/2 = 1

Answer is D

bumpbot · Answer

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If a, b, c, d, e are consecutive positive integers such that a<b<c<d<e

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