A milk-man sells milk after mixing water to it to such a extent that w

Question

A milk-man sells milk after mixing water to it to such a extent that water accounts for 20% of the mixture. If he sells at a mark-up rate of 10%, find his actual profit percentage.

1. 30%
2. 32% 
3. 33.33%
4. 37.5% 
5. 40%

anmit123 · Accepted Answer

Let us assume that cost of milk=100
He sells for 10% profit i.e. for 110
however his cost of milk is only 80 (since 20% is water and only 80% is milk)
now see cost price=80 and sell price=110

% profit= ((110-80)/80)*100=(30/80)*100=37.5%

chetan2u · Answer

80% gone wrong means that we have not been able to understand and convert the question properly.

Ok, the first sentence says that 20% is water, so only 80% is milk. Say 100 litres of mixture contains 80liter of milk.
Next the price has been increased by 10% so if the price was 200, it has become 200+10% of 200=200+20=220.

So, if 100 litre costed 200 earlier, 80 liter would cost (200/100)*80=2*80=160. Now that 80 litre is selling at 220, so a profit of 60 on 160..

As a %, (60/160)*100=600/16=75/2=37.5%

D

Rajat4u · Answer

Assume the total quantity as 100 litre {try this for all similar problems}.
Now for given 20% water in mixture means, 20 L water and 80 L Milk.

Also assume the cost as 1$/litre so CP = 80$ and SP = 100+10%(100) => 110$

NOTE : Marked Price is the price tag on the items. It may or it may not {in case of discounts} be equal to SP.

So profit of 30$ on 80$ which gives 37.5 % profit

QuantMadeEasy · Answer

Lets take price of the mixture is 100, which has price of milk as 80 and of water as 20.

Mark up price is 110% of 100 is 110.

Actual price of milk is 80 and selling price is 110, so profit percent is 30/80*100% = 37.5%.

D is correct.

luisdicampo · Answer

Deconstructing the Question

Water is  20%  of the mixture and costs nothing.
The milk is sold with a  10% markup .
We want the actual profit percentage relative to the true milk cost.

Use easy numbers.

Step-by-step

Assume total mixture =  100  liters.

Water:
 20  liters (cost 0)

Milk:
 80  liters

Let milk cost per liter =  1 .

Total cost:
 80

Selling price per liter with 10% markup:
 1.10

Revenue:
 100 	imes 1.10 = 110

Profit:
 110 - 80 = 30

Profit %:
 30/80 = 37.5\%

Answer: 4 (37.5%)

expeditanatus · Answer

Water = 20 % Milk = 80 %
Profit = 10 %
Actual Profit = 20 + 10 = 30 on cost of 80
For 80 profit is 30
For 100 profit = ?
i.e. (100x30) / 80 = 300/8 = 37.5 %

Answer: 4
 Atul  Mehta

A milk-man sells milk after mixing water to it to such a extent that w

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