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GMATinsight
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Schools: IIM (A) ISB '24
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chetan2u
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GMAT Focus 1: 735 Q90 V89 DI81
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newyork2012
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37^37=(35+2)^37
2^37=2*2^36=2*8^12=2*(7+1)^12
2*1^12=2

B

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Bharath.R
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Hey Chetan,

Can you please elaborate on the Binomial theorem? I am unaware of how to solve this
chetan2u
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Find the remainder when \(37^{37}\) divided by 7 ?

A) 1
B) 2
C) 3
D) 4
E) 6

Source: https://www.GMATisight.com



BINOMIAL THEOREM !! is the savior in such questions..
\(37^{37}=(35+2)^{37}\) divided by 7 will give \(2^{37}\).......

\(2^{37}=(2^3)^{12}*2=8^{12}*2=(7+1)^{12}*2\)..
\((7+1)^{12}*2\) when divided by 7 will leave \(1^{12}*2=2\)

B
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GMATinsight
Find the remainder when \(37^{37}\) divided by 7 ?

A) 1
B) 2
C) 3
D) 4
E) 6


Using modular arithmetic:

37 congruent to 2 modulo 7
\(37^3\) congruent to 8 modulo 7 implies \(37^3\) congruent to -1 modulo 7

Therefore \((37^3)^(12)\) congruent to \((-1)^12\) modulo 7

\(37^(36)\) congruent to 1 modulo 7 Implies \(37^(37)\) congruent to (2*1) modulo 7

Answer = B
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Finding the pattern of occurrence of remainders would help here.

Remainder of 37^1 = 2
Remainder of 37^2 = 4
Remainder of 37^3 = 1
Remainder of 37^4 = 2
Remainder of 37^5 = 4

You start noticing a pattern here. Remainders repeat in a pattern of 3.

So the remainder of 37^37 would be the same as the remainder of 37^4.

Answer (B) 2.
GMATinsight
Find the remainder when \(37^{37}\) divided by 7 ?

A) 1
B) 2
C) 3
D) 4
E) 6

Source: https://www.GMATisight.com
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