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Bunuel
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x^2–7|x|−30=0

Case 1: x> 0

x^2 -7x -30=0. => x^2 -10x +3x -30 =0
=> x = 10, -3; Since x >0, -3 is not possible

Case 2: x <0
x^2 +7x -30=0. => x^2 +10x -3x -30 =0
=> x = -10, 3; Since x<0 , 3 is not possible

Two roots: 10, -10

Product: -100

A
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Bunuel
What is the product of the roots of \(x^2 – 7|x| - 30 = 0\)?

A. -100
B. -9
C. 0
D. 9
E. 100

Hi Bunuel,
Why cannot this equation be solved by definition? Product of roots = c/a for any quadratic equation ax^2+bx+c=0 ?
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Bunuel
What is the product of the roots of \(x^2 – 7|x| - 30 = 0\)?

A. -100
B. -9
C. 0
D. 9
E. 100

Hi Bunuel,
Why cannot this equation be solved by definition? Product of roots = c/a for any quadratic equation ax^2+bx+c=0 ?


cause there is modulus involved
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We need to find what is the product of the roots of \(x^2 – 7|x| - 30 = 0\)?

As we have |x| in the equation so we will have two cases
-Case 1: x ≥ 0
=> |x| = x
=> \(x^2 - 7x - 30 = 0\)
=> \(x^2 -10x + 3x − 30 = 0\)
=> x*( x-10) + 3*(x - 10) = 0
=> (x - 10) * (x + 3) = 0
=> x = 10 or -3

But condition was x ≥ 0
=> x = 10 is a SOLUTION
-Case 2: x ≤ 0
=> |x| = -x
=> \(x^2 + 7x - 30 = 0\)
=> \(x^2 + 10x - 3x − 30 = 0\)
=> x*( x+10) - 3*(x + 10) = 0
=> (x + 10) * (x - 3) = 0
=> x = -10 or 3

But condition was x ≤ 0
=> x = -10 is a SOLUTION

=> Product of the roots = 10 * -10 = -100

So, Answer will be A
Hope it helps!

Watch the following video to MASTER Absolute Values

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