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| As we have |x| in the equation so we will have two cases | |
| -Case 1: x ≥ 0 => |x| = x => \(x^2 - 7x - 30 = 0\) => \(x^2 -10x + 3x − 30 = 0\) => x*( x-10) + 3*(x - 10) = 0 => (x - 10) * (x + 3) = 0 => x = 10 or -3 But condition was x ≥ 0 => x = 10 is a SOLUTION | -Case 2: x ≤ 0 => |x| = -x => \(x^2 + 7x - 30 = 0\) => \(x^2 + 10x - 3x − 30 = 0\) => x*( x+10) - 3*(x + 10) = 0 => (x + 10) * (x - 3) = 0 => x = -10 or 3 But condition was x ≤ 0 => x = -10 is a SOLUTION |
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