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Iwen
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Practice Questions Chat 18 Feb 2024, 20:20
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big relief, thanks!!
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Practice Questions Chat 18 Feb 2024, 20:36
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Iwen
Hey mates, I’ve my first GMAT test Friday, and I’m really worried about one thing but I ca’t find a definitive answer. For the test (especially for the quant section), we just have the board in the computer with the test (awful design) or we have in addition a sheet and a pen??? Tell me the truth even if I’m expecting that your answer is the one that I want haha.
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You might wna practise with the pen and the pad that they actually give at the test centre. It’s not a paper and a pen. It’s a plastic pad with a thin marker.
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Practice Questions Chat 19 Feb 2024, 02:31
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Problem Solving Butler: February 2023
February 19PS 1PS 2

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Bunuel
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Practice Questions Chat 19 Feb 2024, 02:34
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Data Sufficiency Butler: February 2024
February 19DS 1DS 2
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Practice Questions Chat 19 Feb 2024, 10:08
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Bunuel, can you solve this question?

I somehow think the options provided doesn’t have the correct one
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Bunuel
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Practice Questions Chat 19 Feb 2024, 10:14
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Are you getting 63?
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Shubhradeep
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Practice Questions Chat 19 Feb 2024, 10:15
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Did you take lcm (27, 36)=108 and then solve
By that method I got 63
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Bunuel
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Practice Questions Chat 19 Feb 2024, 10:16
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Shubhradeep
Did you take lcm (27, 36)=108 and then solve
By that method I got 63
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­63 looks correct. 
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Practice Questions Chat 19 Feb 2024, 10:18
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But I don’t think we can take the Lcm of the days taken.
Efficiency of 1 woman and efficiency of 1 man will be different.
So, total work done = 12*36*e[woman] = 15*27*e[man]
I think it should be lcm of (12*36, 15*27) = 6480 which we should take as total work

Bunuel
63 looks correct. 
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Can you describe your way?
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Practice Questions Chat 19 Feb 2024, 10:21
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Shubhradeep
But I don’t think we can take the Lcm of the days taken.
Efficiency of 1 woman and efficiency of 1 man will be different.
So, total work done = 12*36*e[woman] = 15*27*e[man]
I think it should be lcm of (12*36, 15*27) = 6480 which we should take as total work

Bunuel
63 looks correct. 
Can you describe your way?
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­
Please post that question in the PS forum: 

https://gmatclub.com/forum/problem-solving-ps-140/ with one of the options as 63. 

Here are posting rules: 

https://gmatclub.com/forum/rules-for-po ... 33935.html 

Thank you!­
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Practice Questions Chat 19 Feb 2024, 10:47
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Shubhradeep
Bunuel, can you solve this question? I somehow think the options provided doesn’t have the correct one
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yes the answer is 63 with total work =15*27 MD.

but since 63 is the multiple of 21 so acc to options i guess 21 will be the correct one
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Practice Questions Chat 19 Feb 2024, 10:58
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Posted a solution here: 

https://gmatclub.com/forum/12-women-can ... l#p3355525

12 women can complete a project in 36 days and 15 men can complete the same project in 27 days. 16 women start working and after 6 days, they were replaced by x men. If x men complete the remaining work in 5 days then what is the value of x?

A. 40
B. 42
C. 45
D. 57
E. 63

­The amount of the work = 12 women * 36 = 15 men * 27

    12w * 36 = 15m * 27
    16w = 15m

The project was done by 16 women working for 6 days and by x men working for 5 days. Hence, the amount of the work also equals to 16w * 6 + 5mx. Equating this to 15m * 27 gives 16w * 6 + 5mx = 15m * 27. Since 16w = 15m, then we'd get:

    15m * 6 + 5m*x = 15m * 27

Reducing by m yields:

    15 * 6 + 5x = 15 * 27

    x = 63.

Answer: E.­­­­
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Practice Questions Chat 19 Feb 2024, 15:26
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can anyone help me with this question please?
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yanichu
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Practice Questions Chat 19 Feb 2024, 15:39
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it would be great if you could help me with this one as well! thank you!!
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Practice Questions Chat 19 Feb 2024, 20:06
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Since k is an integer and k^4 = 32k(2^4*2*k)
k has to be 4k because if you remove the the power you’ll get a 2 from 2^4 and another 2 from 2*k.
So basically k is 4,8,12 etc..i.e. a multiple of 4.
Out of the options 4 is the only multiple of 4.

how-many-3-letter-codes-can-be-formed-by-choosing-without-replacement-421859.html
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Practice Questions Chat 19 Feb 2024, 21:27
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Another approach you can take k=2, k=4 and k=6 since all these number when divided by 32 give the remainder as 2,4,6 resp. Out of these only 4^4 is divisible by 32. Rest are not divisible by 32.
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Practice Questions Chat 19 Feb 2024, 23:40
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This question is discussed in detail here: how-many-3-letter-codes-can-be-formed-by-choosing-without-replacement-421859.html
Hope it helps.

This question is discussed in detail here: when-k-4-is-divided-by-32-the-remainder-is-0-which-of-the-following-345729.html
Hope it helps.
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Practice Questions Chat 20 Feb 2024, 02:34
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Problem Solving Butler: February 2023
February 20PS 1PS 2
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Practice Questions Chat 20 Feb 2024, 02:35
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Data Sufficiency Butler: February 2024
February 20DS 1DS 2
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Practice Questions Chat 20 Feb 2024, 07:21
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Hi guys, I got this question on the Focus Practice Exam 3 wrong.
Q. A train traveled a certain route that consisted of 3 segments, all having exactly the same length. If the average speeds of the train in these segments were 60km/h, 120km/h, 60km/h, what was the average speed of the train, in km/h, over the entire route?

I took a lazy and wrong way of just averaging the 3 speeds and answered 80, which was entirely wrong lol.

So, I then tried to solve it by assuming a distance of 120 for each segment, calculating the total hours based on the 3 speeds, and re-calculating the km/h for the entire route again.

Wondering if there’s a better way to tackle this question?
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