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aayushimehta12
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farhanshrr
Of the 32 students in a certain class, 15 are in a music club and 20 are in a dance club. If 10 of the students are not in either club, how many of the students are in only one of the two clubs?

5
9
10
17
25

Hey guys can some one help me solve this types of questions! and also this one^
­
This question is discussed in detail here: 

https://gmatclub.com/forum/of-the-32-st ... 07976.html

Hope it helps.
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Thank you bunnel! Youre a hero!
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can someone help with this question: A cash register in a certain clothing store is the same distance from two dressing rooms in the store. If the distance between the two dressing rooms is 16 feet, which of the following could be the distance between the cash register and either dressing room?

​normal I period 6 feet​

​II period 12 feet​

​III period 24 feet​.

Answess: I only
II only
III only
I and II
II and III
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farhanshrr
can someone help with this question: A cash register in a certain clothing store is the same distance from two dressing rooms in the store. If the distance between the two dressing rooms is 16 feet, which of the following could be the distance between the cash register and either dressing room?

​normal I period 6 feet​

​II period 12 feet​

​III period 24 feet​.

Answess: I only
II only
III only
I and II
II and III
­
This question is discussed in detail here: 

https://gmatclub.com/forum/a-cash-regis ... 44089.html

Hope it helps.
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hi! does anyone have the solution of this one?
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hi! does anyone have the solution of this one?
5! is the total number of possibilities without any conditions. Then remove the 4 cases where the even numbers are always next to each other. EG. if the first two spots are even numbers, then the remaining 3 can be in 3! ways, multiplied by 2! (the even numbers’ possibilities)..one such case will be 12, therefore 4 will be 48. 120-48=72
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do you have this one as well?
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1 to 12 except 7 and 11
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oh I see, thank you!
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Great question. Interesting approach to the right answer.

MihirBathia
5! is the total number of possibilities without any conditions. Then remove the 4 cases where the even numbers are always next to each other. EG. if the first two spots are even numbers, then the remaining 3 can be in 3! ways, multiplied by 2! (the even numbers’ possibilities)..one such case will be 12, therefore 4 will be 48. 120-48=72
Thank you for your response. This makes sense.
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Because
Probability of getting no divisible by 8 = 3p1+2p1 / 3p2

Please ignore above solution it’s incorrect. Will post correct solution in a while
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