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Natansha
@KarishmaB @BB
Hi, could you please share any specific part from the above solutions you did not understand / got stuck at, or your working on the problem; that way it would be easier to explain you and address your doubt.
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You can do this

for first cycle - T-0 U-5
second cycle - T-2 U-5
third cycle - T-2 U-5

generally for every number ending with 5, the square digits are
(number) *(number+1) and 25

Eg. 25= (2*3)25= 625

so ther remainder is anways going to be 25 in every case
jack5397


Hi ,

I have a doubt what if we try to find a pattern of remainders in this kind of questions

5^1 - 5/50 (Rem-5)
5^2 - 25/50 (Rem-25)
5^3 - 125/50 (Rem-25)
now all the powers will have remainder as 25
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