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given that set P has 5 different prime numbers , median is 13
target is avg mean of P >11 ; i.e. is sum >55
#1
The product of any three numbers of the data set P is odd.
meaning that all values in set P are odd
least value of set P ( 3,5,13,17,19) sum is 57

also for all values of set P sum will be >57
sufficient
#2
The range of the data set P is even.
meaning that all values of set P are odd
and least set value of P will be
( 3,5,13,17,19) sum is 57
sufficient
option D

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If the data set P consists of 5 different prime numbers and has a median of 13, is the average (arithmetic mean) of the data set P greater than 11?

(1) The product of any three numbers of the data set P is odd.
(2) The range of the data set P is even.

 


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If the data set P consists of 5 different prime numbers and has a median of 13, is the average (arithmetic mean) of the data set P greater than 11?

Let us simplify and modify the question.
So the first two numbers could be 2, 3, 5, 7 or 11, while the larger two could be 17, 19 and greater.
The questions asks whether the sum of the 5 prime numbers is greater than 5*11 or 55.
The least total will be 2+3+13+17+19 or 54.
And the next higher sum would be given by replacing 2 by 5 and the total becomes 54-2+5 or 57>55.

Finally the question has become: Is 2 in the set?

(1) The product of any three numbers of the data set P is odd.
This means all number are odd and 2 is not there.
Sufficient

(2) The range of the data set P is even.
The largest would always be odd, so the smallest has to be odd to give range as even.
Again, 2 is out.
Sufficient

D
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If the data set P consists of 5 different prime numbers and has a median of 13, is the average (arithmetic mean) of the data set P greater than 11?

(1) The product of any three numbers of the data set P is odd.

If the products of any three numbers is odd, then the minimum number of the data can't take 2. Therefore, the minimum data set of P 3,5,13,17,19 will have an average greater than 11.
Sufficient.

(2) The range of the data set P is even.

If the range is even, then again the minimum number of the data can't take 2. Same situation as in statement 1. Hence, it's sufficient too.

Option D.
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Given: set of 5 numbers that are prime with median = 13 (_ , _ , 13 , _ , _)
To find: If average of numbers >11 = sum of numbers >55

The prime numbers that are less than 13 = 2,3,5,7,11

(1) The product of any three numbers of the data set P is odd.
(2) The range of the data set P is even.

Statement 1:
As the product is odd, 2 cannot be one of the prime numbers as that would result in the product being even
Assuming we use 3, 5, 17, 19 for the remaining numbers to create the smallest total, the sum would be greater than 55.
Therefore the use of any prime numbers that are equal or greater than the above numbers will lead to an average that is greater than 11
Statement 1 is sufficient
Eliminate Options B, C, E

Statement 2:
Rage of set is even = largest number - smallest number
Since 2 is the only even prime number, it would have to be eliminated as only an odd number subtracted from another odd number will result in an even range
Using the same logic from above, it will lead to an average that is greater than 11
Statement 2 is sufficient

Therefore the correct option is D
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