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m>n,

Even integers between 2m and 2n ?

Case 1. (2,1) => (4,2) even integers 0
Only B and D matches
Case 2: (3,1) => (6,2) 1 even integer, 4.
Only B matches.

B is the answer



Bunuel
If m and n are positive integers and m > n, then how many even integers are there between 2m and 2n, excluding 2m and 2n?

A. m - n
B. m - n - 1
C. m - n + 1
D. 2m - 2n - 1
E. 2m - 2n + 1

­
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n<m
Even integers between 2m and 2n
Let, m= 3 and n= 1
Between 6 & 2, there is one even integer (4)
m-n-1= 3-1-1= 1

Let, m= 5 and n= 1
Between 10 & 2, there are three even integers (4,6,8)
m-n-1= 5-1-1= 3

Answer: B
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Bunuel
If m and n are positive integers and m > n, then how many even integers are there between 2m and 2n, excluding 2m and 2n?

A. m - n
B. m - n - 1
C. m - n + 1
D. 2m - 2n - 1
E. 2m - 2n + 1
let, m = 3 and n = 2
2m = 6 and 2n = 4
even integers between 2m and 2n = 0

A. m - n = 3-2 = 1
B. m - n - 1 = 3-2-1 = 0
C. m - n + 1. =3-2+1 = 2
D. 2m - 2n - 1 = 6 - 4 - 1 = 1
E. 2m - 2n + 1 = 6 - 4 + 1 = 3

Answer: Option B
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Bunuel
If m and n are positive integers and m > n, then how many even integers are there between 2m and 2n, excluding 2m and 2n?

A. m - n
B. m - n - 1
C. m - n + 1
D. 2m - 2n - 1
E. 2m - 2n + 1

­
Given: m and n are positive integers m,n >0

m > n

We get, m>n>0

How many even numbers are between 2m and 2n ?


let’s take m= 2, n=1

2m =4 and 2n =2 . Even numbers between 4 and 2 is zero.

A. m - n = 2-1 =1. Eliminated

B. m - n - 1 = 2-1-1 = 0

C. m - n + 1 = 2-1+1 = 2. Eliminated

D. 2m - 2n - 1 = 4-2-1= 1 Eliminated

E. 2m - 2n + 1 = 4-2+1 =3 Eliminated

Option B
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