Hi AmishaShah1234,Great eye, and this is exactly the hinge that MS05's reasoning turns on. MS05 wrote
"Since a team is 'multi-member,' a ≥ 2" - and your question is whether that step is safe. It is, and here's why.
The word "multi-member" is doing the work. "Multi" means
more than one, so by definition
every team in this competition has more than one member. A single-member team wouldn't be a
multi-member team at all - the stem isn't describing one special kind of team, it's telling you what all the teams are like. On top of that, the stem says each team has
'a' members - one shared value - so the teams are uniform, not a mix of sizes. That locks in
a ≥ 2, with
a an integer.
Why this matters for the AN column. Teams in round
3 =
54, so employees in round
3 =
54 × a. Now scan the options for a value equal to
54 × (integer ≥
2):
-
54 ×
1 =
54 - this is the trap you spotted, but it needs a =
1, which "multi-member" forbids.
-
54 ×
9 =
486 - valid, with a =
9.
-
81,
243,
384 aren't multiples of
54 at all.
Therefore, the "multi-member" wording is precisely what rules out
54 and leaves
486 as the only workable value for AN.
Flip the word to feel the trap: if the stem had said "each
team has
a members" (dropping "multi-member"), then a =
1 would be allowed, and
54 would suddenly be a legitimate answer for AN. That one adjective is the whole difference - it's not decorative, it's a constraint.
Answer: Column 1 (M) = 486; Column 2 (AN) = 486AmishaShah1234
The question says, "
Each multi-member team" has 'a' members but does not specify that there are no single member teams..