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A survey was conducted among the tenants of the Arconia building about their support for two propositions, X and Y. The ratio of the number of tenants who support proposition X to the number who support both X and Y is 3 to 2. The ratio of the number of tenants who support proposition Y to the number who support both propositions is twice that ratio. The ratio of the number of tenants who support neither proposition to the number who support both propositions is half the first ratio. What is the ratio of the number of tenants who support only proposition X to the number who support only proposition Y?

A. 1 : 4
B. 1 : 3
C. 1 : 2
D. 3 : 1
E. 4 : 1

use 2x2 matrix

-----X----NX----total
Y----A---- ----
NY-- ---- ----
let both be A

X / both = (3/2)A
support Y to both = 3/2 * 2 A = 3A
Only X 3/2 A - A = 1/2 A
support only Y = 3A-A ; 2A
X : y = 1/2A / 2A ; 1:4
OPTION A
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We can apply set theory here.
Let's consider no. of tenants who supports propositions only X is x, only Y is y and both is b.
Total supports of X = x+b
Total supports of Y = y+b

Given : (x+b)/b=3/2 & (y+b)/b= 2* (3/2) = 3
After solving, we can get x/y = 1:4.
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X:B= 3:2
Y:B= twice the ratio of 3:2 is 3:1, (basically multiple 3:2 x 2)
N:B= 3:4

Only X: Only Y?

Only X= X-both => 3/2 B - B= 1/2B
Only Y= Y-both=>3B-B=2B

Only X: Only Y= 1/2 B divided by 2/1 B= 1/4


Bunuel
A survey was conducted among the tenants of the Arconia building about their support for two propositions, X and Y. The ratio of the number of tenants who support proposition X to the number who support both X and Y is 3 to 2. The ratio of the number of tenants who support proposition Y to the number who support both propositions is twice that ratio. The ratio of the number of tenants who support neither proposition to the number who support both propositions is half the first ratio. What is the ratio of the number of tenants who support only proposition X to the number who support only proposition Y?

A. 1 : 4
B. 1 : 3
C. 1 : 2
D. 3 : 1
E. 4 : 1

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Imagine a Venn diagram: with two overlapping sets of X and Y.

I have considered only X as A, Only Y as C, both X and Y as B and none part as N.

From the question we are said: (x + b) / b = 3/2
=> 2x = b
= x = b/2 ...... (1)
(y+b)/b = twice of the previous fraction which is (2*3/2) = 3
=> y = 2b ...... (2)

I didn't really see the use of using N.
So from the above 2:

x/y = 1/4. Hence A.


Bunuel
A survey was conducted among the tenants of the Arconia building about their support for two propositions, X and Y. The ratio of the number of tenants who support proposition X to the number who support both X and Y is 3 to 2. The ratio of the number of tenants who support proposition Y to the number who support both propositions is twice that ratio. The ratio of the number of tenants who support neither proposition to the number who support both propositions is half the first ratio. What is the ratio of the number of tenants who support only proposition X to the number who support only proposition Y?

A. 1 : 4
B. 1 : 3
C. 1 : 2
D. 3 : 1
E. 4 : 1

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Given that the questions mention all data in ratios including the required answer being a ratio, we can assume numbers for our calculation.

Neither X nor Y/ Both X and Y = 3/4

Let Neither X nor Y be 3 and Both X and Y be 4

Y/ Both X and Y = 3/1 or 12/4

X/ Both X and Y = 3/2 or 6/4

Only X/ Only Y = (6-4)/(12-4) =2/8=1/4

Therefore, Option A
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Bunuel
A survey was conducted among the tenants of the Arconia building about their support for two propositions, X and Y. The ratio of the number of tenants who support proposition X to the number who support both X and Y is 3 to 2. The ratio of the number of tenants who support proposition Y to the number who support both propositions is twice that ratio. The ratio of the number of tenants who support neither proposition to the number who support both propositions is half the first ratio. What is the ratio of the number of tenants who support only proposition X to the number who support only proposition Y?

A. 1 : 4
B. 1 : 3
C. 1 : 2
D. 3 : 1
E. 4 : 1

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Ans: Option C
X : (X&Y) = 3:2
Y : (X&Y) = 3:1
None : (X&Y) = 3:4
In all 3 ratios, (X&Y) is common. Lets make the values same of (X&Y) same in all 3 ratios by taking LCM of 2,1,4 which is 4.
Thus, the ratios become
X : (X&Y) = 6:4
y : (X&Y) = 12:4
None : (X&Y) = 3:4
So, X : Y = 6:12 = 1:2.
Thus, Option C
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Im not sure if this is correct

4 variables:
x - only support stand x
y - only support stand y
z - support both x and y
n - support neither

so we have:

x/z = 3/2 => 2x=3z
y/z = 3/1 => y=3z
n/z = 3/4

atp we have an easy:

2x=y
=> x/y = 1/2
(c)
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let x = x only, y = y only, b = both, n = none
Acc. to statement 1: x+b/b = 3/2
Acc. to statement 2: y+b/b = 3
Acc. to statement 3: n/b = 3/4

need x/y -> from 1 and 2 => x/b = 1/2 and y/b = 2 => x/y = 1/4
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Lets consider

Total number of tenants = T
number of tenants who support proposition X = X
number of tenants who support proposition Y = Y
number of tenants who support proposition X nor proposition Y = B
number of tenants who support neither proposition = N
number of tenants who support only X = Ox ( X not Y)
number of tenants who support only Y = Oy ( Y not X)

we need to find ration of Ox / Oy = ?

From question we can observe that
X = Ox + B ------> equation 1
Y = Oy + B ------> equation 2

Now, lets try to understand the 3 ratios given in question
1) Ratio of X and B = 3:2
X/B = 3/2 -------> first ratio
X = 3*B/2

lets substitute X value in equation 1 , such that 3B/2 = Ox + B => 3B/2 - B = Ox
B/2 = Ox -------> equation 3
Therefor we can observe that, number of tenants who support only proposition X are half the number of tenants who support both proposition X and proposition Y

2) Ratio of Y and B = twice the first ratio
Y/B = 2*(3/2)
Y/B = 3
Y = 3*B

let substitute Y value in equation2 , such that 3B = Oy + B => 3B -B = Oy
2B = Oy-------> equation 4
Therefor we can observe that, number of tenants who support only proposition Y are twice the number of tenants who support both proposition X and proposition Y

3) Ratio of N(neither) to B [Note : no need to find this, above equation 3 and equation 4 are enough to answer]
N/B = half the first ratio
N/B = 1/2 * (3/2) = 3/4
N = (3/4)*B

Therefor we can observe that, number of tenants who support neither proposition X nor proposition Y is (3/4) of number of tenants who support both proposition X and proposition Y

Now, lets divide equation 3 / equation 4, i.e.,

Ox = B/2
Oy = 2B

Ox/Oy = 1/4 [Note : cancel B]

Therefor, Ox:Oy = 1:4
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a = only X, b = only Y, c = both, d =neither
(a+c) : c = 2 : 3 => a = 1/2c
(b+c) : c = 3:1 => b=2c
So a : b = 1/2c : 2c => 1 :4
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X Y X+Y ~(X+Y)
3 2
3 1
4 3
taking LCM for X+Y, LCM(2,1,4)=4
Thus equating all ratios for X+Y to 4, we get

X Y X+Y ~(X+Y)
6 12 4 3

X/Y = 6/12 = 1/2
Option C

Bunuel
A survey was conducted among the tenants of the Arconia building about their support for two propositions, X and Y. The ratio of the number of tenants who support proposition X to the number who support both X and Y is 3 to 2. The ratio of the number of tenants who support proposition Y to the number who support both propositions is twice that ratio. The ratio of the number of tenants who support neither proposition to the number who support both propositions is half the first ratio. What is the ratio of the number of tenants who support only proposition X to the number who support only proposition Y?

A. 1 : 4
B. 1 : 3
C. 1 : 2
D. 3 : 1
E. 4 : 1

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x:x&y:y
3:2:4

x-x&y:y-x&y
1:2

1:2 is answer
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Let those who only support X : Who support both X & Y be 3p : 2p (giving the ratio a variable for calculation)
Therefore, those who only support X would be, Those supporting X (minus) those supporting both X & Y = Supporters of only X

3p - 2p = p (supporters of only X)

Similarly, Those supporting Y : those supporting both X & Y will be 6p : 2p
Supporters of only Y = 6p - 2p = 4p

Ratio of only X to only Y = 1p : 4p or 1 : 4
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X = 3x
both= 2x
only X =x

Y=3y
both=y
only Y = 2Y

only X / only Y = x/2y
now, 2x=y from both
only X/ only Y =1/4

Ans A
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Let those that support both be b meaning x/b= 3/2= x=3/2b
Y to b= 3/2x2= 3b
None= 3/2x1/2= 3/4b
Only X= 3/2Bb-b= 1/2b
Only Y= 3b-b= 2b
X;Y =1/2b;2b
=1:4
Ans: A
Bunuel
A survey was conducted among the tenants of the Arconia building about their support for two propositions, X and Y. The ratio of the number of tenants who support proposition X to the number who support both X and Y is 3 to 2. The ratio of the number of tenants who support proposition Y to the number who support both propositions is twice that ratio. The ratio of the number of tenants who support neither proposition to the number who support both propositions is half the first ratio. What is the ratio of the number of tenants who support only proposition X to the number who support only proposition Y?

A. 1 : 4
B. 1 : 3
C. 1 : 2
D. 3 : 1
E. 4 : 1

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Ratio of proposition X to both (X and Y) = 3:2 ...(1)
Ratio of proposition Y to both (X and Y) = 6:2 ...(2)

Ration of neither X nor Y to both (X and Y) = 3:4 (This is not required though)

From above 1 & 2
We get, proposition of only X to only Y = 1:4

So, answer is A
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Bunuel
A survey was conducted among the tenants of the Arconia building about their support for two propositions, X and Y. The ratio of the number of tenants who support proposition X to the number who support both X and Y is 3 to 2. The ratio of the number of tenants who support proposition Y to the number who support both propositions is twice that ratio. The ratio of the number of tenants who support neither proposition to the number who support both propositions is half the first ratio. What is the ratio of the number of tenants who support only proposition X to the number who support only proposition Y?

A. 1 : 4
B. 1 : 3
C. 1 : 2
D. 3 : 1
E. 4 : 1

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1st --> X:B = 3:2

2nd --> Y:B = 3:1

3rd --> N:B = 3:4

we want X:Y

solving 1 and 2
Taking LCM (2,1) so that we can make B value same in both ratios

X:B = 3:2 and Y:B = 6:2

we want only X --> x - both = 3-2 = 1
we want only Y --> y - both = 6-2 = 4

So, Final X:Y = 1:4
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