Lets consider
Total number of students T = 90
number of students in debate club = D
number of students in math club = M
number of students in only debate club = Od
number of students in only math club = Om
number of students in both clubs = B
every student participates in atleast one club => T = Od + Om + B ----> Equation 1
we know D > M
total members in each club, D = Od + b and M = Om + B
Od + B > Om + B
Cancel B on both sides
so is, Od > Om ?
lets check the statement 1 : 3/5 of students participate in only math club
only math club => Om = 3/5 * 90 = 54 students
substitute in Equation 1
90 = Od + 54 + B
Od + B [total number of students in debate club] =90 -54 = 36 = D
when we compare, D = 36 and M = Om + B = 54 + B
B is number of students in both clubs, must be a positive numberi .e., B >= 0
since M = 54+ B , M must be greater than or equal to 54
D = 36 and M >= 54
we can definitely answer,
statement 1 is sufficientnow lets check statement 2 : 2/9 of students participate in both debate club and math club
B = 2/9 * 90 = 20 students
Substitute in equation 1 => 90 = Od + Om+ 20
Od + Om = 70
Is Od > Om ?
Case 1 : if Od is larger
let Od = 40, Om = 30, then Od > Om
Case 2 : Om is larger
Od = 30 and Om = 40 then Od < Om
as we have both answers yes and no,
Statement 2 is not sufficient