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It is given that each student participates in at least 1 of 2 activities: Debate Club or Math Club

Total Students = 90

Question: number of students who participate in Debate Club > number of students who participate in Math Club

We need to identify if this question can be answered using given options.

(1) 3/5 students participate in only Math Club, which leaves 2/5 students who can participate in Debate Club. Since 3/5 >2/5, number of students participate in Math Club is definitely more than Debate Club.

This implies that the answer to the question is no and Option (1) provides enough information to answer this question.

Hence (1) is sufficient.

(2) 2/9 of the students participates in both the clubs. Using this information, we cannot compare number of students who participate in Debate Club compared to Math Club.

Hence (2) is not sufficient.

The correct answer is (A)
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90 students participating in at least of the clubs
Problem Statement: Debate club participation is greater than math club?

Statement 1: 3/5 are in only math club which means 54 students are only in math club which is more than half of the students which concludes debate club will have less number than math club. Sufficient

Statement 2: 2/9 are in both clubs. 20 students are in both clubs. from this we cannot compare students in both the clubs. Not Sufficient.

So, correct answer is A
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Bunuel
A survey of 90 students found that each student participates in at least one of two activities: Debate Club or Math Club. Is the number of students who participate in Debate Club greater than the number who participate in Math Club?

(1) 3/5 of the students participate in only Math Club.
(2) 2/9 of the students participate in both Debate Club and Math Club.

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Total students surveyed = 90

Each student participate in at least one of the two activities : Debate club (DC) and Math club (MC)

we need to find : Is DC > MC ?

for questions like this, a definite yes or no is considered as sufficient.

let’s assume: Debate club members only as a, math club members only as c, and both DC and MC as b.

neither of the two is taken as d.

since all participate in at least one activity, d =0.

a+b+c = 90

Statement 1:

3/5 of the students participate in Only Math club.

(3/5)*90 = 54 students participate in ONLY math club = C

c = 54

This leaves us with a+b = 90-54 = 46

Is DC > MC ?

(a+b) > (b+c) ?

Is a> c ?

since, c = 54, even if we consider b = 0, a can take the max value of 46.

Hence, we can say concretely Is DC > MC ? NO

Sufficient

Statement 2:

(2/9) of the students participate in both debate club and maths club.

(2/9)*90 = 20 students = b

This, leaves us with a+c = 70

The values of an and c can take many different combinations.

For certain values a> c and for some c>an and we also have a case of a=c=35.

Hence, Insufficient

Option A
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Debate > Math??

1. if only math 60%, then debate has to be less than 40%. SUFFICIENT.
2. 2/9*90= 20 .. it can be 50+20+20 ..or, 20+20+50 .. NOT SUFFICIENT.

Ans A
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Total sts: 90

1) 3/5 = 54 sts participate in Only maths club.
Remaining sts = 36, hence the no of sts in debate club is 36, in which some sts could also be in maths club.

This clearly means no of sts in debate club< in maths club
Ans No, clearly Sufficient

2) 2/9 = 20 sts in both clubs, couldn't derive anything else.

Ans A
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S1 is sufficient because 3/5 is already more than half the total meaning there is no way those in debate club can be more than those in math club
S2 Insufficient since we do not know about the distribution of the rest 70 who are the majority so cannot determine
Ans A
Bunuel
A survey of 90 students found that each student participates in at least one of two activities: Debate Club or Math Club. Is the number of students who participate in Debate Club greater than the number who participate in Math Club?

(1) 3/5 of the students participate in only Math Club.
(2) 2/9 of the students participate in both Debate Club and Math Club.

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Bunuel
A survey of 90 students found that each student participates in at least one of two activities: Debate Club or Math Club. Is the number of students who participate in Debate Club greater than the number who participate in Math Club?

(1) 3/5 of the students participate in only Math Club.
(2) 2/9 of the students participate in both Debate Club and Math Club.

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1) 3/5(90) = 54 --> Only Math

90-54 = 36 --> could be only Debate or Both

case 1: Assume all 36 are only Debate and 54 are only Math then --> Debate < Math
case 2: Assume all 36 are both Debate and Math and 54 are only Math then --> Debate < Math

Hence Statement 1 alone is sufficient.

2) 2/9(90) = 20 --> Both

90-20 = 70 --> remaining students (split between only debate and only math)

we can have different split combinations like 35 only debate, 35 only math or 60 only debate and 10 only math and So on.
Hence we cannot come to a single conclusion to answer is debate is greater than math.

Hence Statement 2 is not sufficient

So it's option A --> Statement 1 alone is sufficient.
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Ans: A
1. 3/5 of 90 students is 54 students who are only math, which leaves us with 36 students which can be divided among Both Math and Debate or only Debate, in either case Math is greater than the Debate club.
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Lets consider

Total number of students T = 90
number of students in debate club = D
number of students in math club = M
number of students in only debate club = Od
number of students in only math club = Om
number of students in both clubs = B

every student participates in atleast one club => T = Od + Om + B ----> Equation 1
we know D > M
total members in each club, D = Od + b and M = Om + B

Od + B > Om + B
Cancel B on both sides
so is, Od > Om ?

lets check the statement 1 : 3/5 of students participate in only math club

only math club => Om = 3/5 * 90 = 54 students
substitute in Equation 1
90 = Od + 54 + B
Od + B [total number of students in debate club] =90 -54 = 36 = D

when we compare, D = 36 and M = Om + B = 54 + B
B is number of students in both clubs, must be a positive numberi .e., B >= 0
since M = 54+ B , M must be greater than or equal to 54

D = 36 and M >= 54

we can definitely answer, statement 1 is sufficient

now lets check statement 2 : 2/9 of students participate in both debate club and math club

B = 2/9 * 90 = 20 students

Substitute in equation 1 => 90 = Od + Om+ 20
Od + Om = 70

Is Od > Om ?

Case 1 : if Od is larger
let Od = 40, Om = 30, then Od > Om

Case 2 : Om is larger
Od = 30 and Om = 40 then Od < Om

as we have both answers yes and no, Statement 2 is not sufficient
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D: only Debate Club
M: only Math Club
B: both

D+M+B=90

question:
D+B > M+B?
equivalent to:
D > M?

(1)
M = 90 * 3/5 = 54
D+B = 90-54 = 36
As M=54 is greater than D+B=36, for sure M+B (B is non negative) is greater than D+B, The answer is no.

Sufficient

(2)
B = 90 * 2/9 = 20
D+M = 90-20 = 70

If D=36 and M=34 the answer is yes.
If D=34 and M=36 the answer is no.

Insufficient

IMO A
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Each student participates in at least one of two activities:
Debate only + Math only + Both = 90 (a)

(1)
Math only = 3/5 of 90 = 54

Sustituting in (a):
Debate only + 54 + Both = 90
Debate only + Both = 36

Debate = Debate only + Both = 36
Math = Math only + Both = 54 + Both

Is 36 > 54 + Both?. No, because Both is zero or positive.

Condition sufficient

(2)
Both = 2/9 of 90 = 20

Sustituting in (a):
Debate only + Math only = 70

No enough info to decide if Debate > Math.

Condition insufficient

Answer A
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Total = only D + only M + both = 90

(1)
only M = 90 x 3/5 = 54
only D + both = 90-54 = 36

If only M is greater than (only D + both) then (only M + both) is greater than (only D + both) and the answer is no.

Condition (1) is sufficient

(2)
both = 90 x 2/9 = 20

Is (only M + both)=(only M + 20) greater than (only D + both)=(only D + 20)?
Is (only M) greater than (only D)?

There is not enough information to give a single answer

Condition (2) is insufficient

The answer is A
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90 students must participate in at least one of the following club D (debate) or club M (math)

3/5 students ONLY participate in math club. Meaning at least 3/5 participate in math, and NOT in debate. 3/5*90 = 18*3 = 54

54 of 90 students participate in math and not debate.

A is sufficent becuase we know the smallest possible number of members for Math club is greater than the largest possible numbers of debate club.

AD
BCE

2)

2/9 (20 students) participate in both. I have 70 students remaining that either participate in Math or Debate. I could have an even split, There could be all 70 in Math, there could be 50 in debate & 20 in math. I don't know the aligence of the remaining 70 students, therefore I cannot know which club has a greater amount of members.

AD
BCE

Option: A

Bunuel
A survey of 90 students found that each student participates in at least one of two activities: Debate Club or Math Club. Is the number of students who participate in Debate Club greater than the number who participate in Math Club?

(1) 3/5 of the students participate in only Math Club.
(2) 2/9 of the students participate in both Debate Club and Math Club.

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total = debate + math - both + neither
neither = 0

90 = debate + math - both

debate > math?

(1)
math - both = 90*3/5 = 54
90 = debate + 54
debate = 36

debate > math?
36 > 54 + both? -> answer is NO

Sufficient

(2)
both = 90*2/9 = 20
90 = debate + math - 20
debate + math = 110

debate > math? -> NOT SURE

Insufficient

The correct answer is A
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This is a classical tricky overlapping sets problem. We know that every student participates in atleast one activity. We need to find out whether number of students who participate in Debate Club is greater than number who participates in Math Club. Lets have a look on 1st Statement.

1. It says 3/5 of the students participate in only Math Club. It means 54 students participates in only Math club. This implies that 90-54 =36 students participate in Debate club. This is sufficient since students participating in Math Club will be greater than or equal to 54. Whereas students participate in Debate Club is 36. So we can answer the question.

2. It says 2/9 of the students participate in both Debate and Math Club which is equal to 20 students. But no other information related to students participation in Math and Debate club is provided and lots of combination can come into picture. So this is insufficient.

So the answer is A.
Bunuel
A survey of 90 students found that each student participates in at least one of two activities: Debate Club or Math Club. Is the number of students who participate in Debate Club greater than the number who participate in Math Club?

(1) 3/5 of the students participate in only Math Club.
(2) 2/9 of the students participate in both Debate Club and Math Club.

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Bunuel
A survey of 90 students found that each student participates in at least one of two activities: Debate Club or Math Club. Is the number of students who participate in Debate Club greater than the number who participate in Math Club?

(1) 3/5 of the students participate in only Math Club.
(2) 2/9 of the students participate in both Debate Club and Math Club.

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Given,
DD'T
Mm
M'0
Td90

To find: Is d>m?

Statement 1
3/5 students only in Math club, 54 only in Math club
DD'T
M54m
M'0
T365490
Debate club students are 36, Math Club students are atleast 54.
Is d > m? No

Sufficient. AD/BCE


Statement 2
2/9 students in both , 20 in both
DD'T
M20
M'0
T90
We can only say that both D and M atleast has to be 20 and the sum of D only + M only is 70. We cannot compare them.

InSufficient. AD/BCE

Correct Answer: A
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Total Students = 90
Condition = Every student is in at least one club (there are no students in neither )
The Question : Is D>M ?

Let’s define 3 distinct groups :
1. Only debate = d
2. Only Maths = m
3. Both = b

We know that
d+ m + b = 90

And the total of debate D = d+b
And total of maths M = m+ b
Therefore the question D>M is equivalent to d> m ?

Now ,
Statement 1
m = (3/5 )* 90 = 54
m = 54
If m is 54 , then the remaining students (d+b) must be equal to 90-54=36
Since D= d+b , we know D = 36
And M = m+ b = 54+b
Even if b = 0 , Math club (54) is already larger than Debate Club (36)

Hence we can say statement 1 alone is Sufficient

Statement 2

b= (2/9)* 90 = 20
This tells us d+m = 70
However we don’t know the split between d and m
We can’t give a definite Yes or No
Hence this statement is not sufficient


Final Answer :
A
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