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16 Dec 2025, 21:28
Kudos
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given that
\(\bar{D} \text{ and } \bar{M} = 0\)
question: is \(D > M\) ?
Statment 1:
\(M \text{ and } \bar{D} = \frac{3}{5}\)
then, \(\bar{D} = \frac{3}{5}\)
then, \( D = 1-\bar{D} = \frac{2}{5}\)
we know that already \(M \text{ and } \bar{D} = \frac{3}{5}\)
so \(M > 3/5\)
Statement is sufficient to answer if \(D > M\)
Statement 2:
given,
\(M \text{ and } D = \frac{2}{9}\)
from this we cannot determine M or D info completely.
It is insufficient
Ans: option A
\(\bar{D} \text{ and } \bar{M} = 0\)
question: is \(D > M\) ?
Statment 1:
\(M \text{ and } \bar{D} = \frac{3}{5}\)
then, \(\bar{D} = \frac{3}{5}\)
then, \( D = 1-\bar{D} = \frac{2}{5}\)
we know that already \(M \text{ and } \bar{D} = \frac{3}{5}\)
so \(M > 3/5\)
Statement is sufficient to answer if \(D > M\)
Statement 2:
given,
\(M \text{ and } D = \frac{2}{9}\)
from this we cannot determine M or D info completely.
It is insufficient
Ans: option A
16 Dec 2025, 23:10
Kudos
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what we have :
Total = 90
Neither = 0
Statement A : 3/5th are in math's club only
so 2/5 * 90 = 54
so remaining is 90 - 54 = 36
So we can see even if Debates students are 36 then also Maths > Debate student
Statement 1 is sufficient
Statement 2 : it just tell us the number of both students : 2/9 * 90 = 20
But we don't know if M + 20 >/=/< D + 20
Statement 2 is not sufficient
So Answer is A
Total = 90
Neither = 0
Statement A : 3/5th are in math's club only
so 2/5 * 90 = 54
so remaining is 90 - 54 = 36
So we can see even if Debates students are 36 then also Maths > Debate student
Statement 1 is sufficient
Statement 2 : it just tell us the number of both students : 2/9 * 90 = 20
But we don't know if M + 20 >/=/< D + 20
Statement 2 is not sufficient
So Answer is A
yuvrajbhama
Posts: 37
16 Dec 2025, 23:12
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SO THE QUESTION ASKS IS NUMBER OF STUDENTS MORE IN DEBATE THAN IN MATH? YES/NO
IMAGIN IT TO ONLY THREE OPTION AVAILABLE TO STUDENTS
ONLY MATH=A
ONLY DEBATE=B
BOTH MATH AND DEBATE=C
1) 3/5= ONLY MATH WHICH IS EQUAL TO 60% OF 90 I.E. 54(9*6)
WHICH DFINATELY HELPS TO ANSWER
2) 2/9 OF 90 IS CHOOSING BOTH I.E. C= 20. DOESIT HELP TO ANSWER THE QUESTION INDIVIDUALLY NNNNNNNNNNNNNNNNNO
CORRECT ANSWER IS A
IMAGIN IT TO ONLY THREE OPTION AVAILABLE TO STUDENTS
ONLY MATH=A
ONLY DEBATE=B
BOTH MATH AND DEBATE=C
1) 3/5= ONLY MATH WHICH IS EQUAL TO 60% OF 90 I.E. 54(9*6)
WHICH DFINATELY HELPS TO ANSWER
2) 2/9 OF 90 IS CHOOSING BOTH I.E. C= 20. DOESIT HELP TO ANSWER THE QUESTION INDIVIDUALLY NNNNNNNNNNNNNNNNNO
CORRECT ANSWER IS A
Bunuel
