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17 Dec 2025, 12:41
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N = 1000
E = 1600
After 4 months, let x and y are new users gained every month for N and E respectively,
N = 1000 + 4x
E = 1600 + 4y
(1000 + 4x) = 250% of (1600 + 4y)
On solving x = (1500 + 5y)/2
On trying different combination from the options, the one which satisfy is: x = 1500, y = 300
E = 1600
After 4 months, let x and y are new users gained every month for N and E respectively,
N = 1000 + 4x
E = 1600 + 4y
(1000 + 4x) = 250% of (1600 + 4y)
On solving x = (1500 + 5y)/2
On trying different combination from the options, the one which satisfy is: x = 1500, y = 300
17 Dec 2025, 13:06
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Bookmarks
Bunuel
Using arithmetic growth formula here. We know that Nexus will be 3.5 times Echo (250% more).
Let \(k_1\) equal growth factor for Nexus and \(k_2\) equal growth factor for Echo.
\(4k_1+1,000=\frac{7}{2}(4k_2+1,600)\)
Simplifying, we get:
\(2k_1-7k_2=2,300\)
We're looking for values for \(k_1\) and \(k_2\) here that equal 2,300. We can tell from the equation that \(k_1\) needs to be a far bigger value than \(k_2\) and needs to make a multiple of 7 when subtracted from 2,300.
Trying 3,600 first we get:
\(2(3,600)-7k_2=2,300\)
\(-7k_2=-4,900\)
\(k_2=700\)
Thus Nexus grows at 3,600 a month and Echo grows at 700 a month.
