Plan A
Let the one time entry fee be E
Then the parking fee = E + (t - 2)*x
where t is the number of hours of parking
Plan B
First hour = 3x/2
Additional hour = 3x/2
So parking fee = t*(3x) / 2
Given that the parking was for 3 hr 20 minutes. So the driver needs to pay for 4 hours.
According to plan A, fee becomes E + 2x
According to plan B, fee becomes 6x
Since both plans would charge same amount,
E + 2x = 6x
E = 4x
Total charge for plan B = 6x
So E : B = 2:3
We can make this ratio only with 8 and 12 from the available options.
Hence Entry for A = 8,
Total charge for B = 12
Bunuel
Gift
12 Days of Christmas Competition
This question is part of our holiday event
Win $40,000 in prizes: courses, tests, and more
A driver is choosing between two pricing plans for evening parking in a downtown garage.
• Plan A charges a one time entry fee that covers the first 2 hours, plus $x for each additional hour or fraction of an hour beyond the first 2 hours.
• Plan B charges no entry fee, but charges $3x/2 for the first hour and $3x/2 for each additional hour or fraction of an hour beyond the first hour.
Select for
Plan A entry fee and for
Plan B total charge the two figures, in US dollars ($), that could be Plan A's entry fee and Plan B’s total charge for 3 hours and 20 minutes such that both plans would charge the same total amount. Make only two selections, one in each column.