Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Aug 2710:00 AM EDT
-11:00 AM EDT
We’ve worked incredibly hard to build TTP into the best test prep experience possible, and it would mean a lot to us to win Newsweek’s 2026 Readers’ Choice Award for Best Test Prep. If TTP has helped you, we’d be incredibly grateful for your vote.
Sep 0201:00 PM EDT
-11:59 PM EDT
Take 30% off all study plans with code COURSEWORK - Expires on Monday 9/7
Sep 0410:00 AM PDT
-11:00 AM PDT
What does test anxiety really look like on the GMAT? For many test takers, it does not look like a panic attack. Instead, it shows up as brain fog, rereading, negative comparisons, mental noise....
Sep 0609:30 AM EDT
-12:30 PM EST
Top scores are possible when you enroll in a powerful EA course, taught live online + 6 months access to TTP OnDemand video courses included! Perfect class schedule and easy course access for working professionals. Class starts Sundays Sept. 6, 2026.- Sep 07
12:01 AM PDT
-11:59 PM PDT
On the 7th, GMAT Club Tests will be Free! Including all the Quizzes, Questions, and Tests. 12 AM - 11:59 PM PDT - Sep 09
07:00 AM PDT
-10:00 AM PDT
Meet AdComs and explore top Master’s programs - MiM, MiF, MSc, MSBA and more. - Application Fee Waivers - Free 1-Week of GMAT Club Tests: - Master's Application Toolkit - Grand Prize Giveaway 
Sep 1507:00 PM EDT
-09:00 PM EST
Elite scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thurs Sept. 15, 2026 - Nov. 15, 2027, 7:00pm-9:00pm EST
Sep 2108:00 PM EDT
-10:00 PM EDT
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included! Class starts Mon, Tues, Wed, Thur, Fri Sept. 21, 2026 - Oct. 9, 2027, 7:00pm-10:00pm EST
07 Jul 2026, 15:18
Kudos
Bookmarks
The Correct answer is D. Either Statement alone is sufficient.
Lets assume that number of students enrolled in
Only Photography is x
Only Ceramics is y
and both is z
Now, we have been given that x+y+z=54 ---------(1)
And also, that y=18 ( how? out of 54 students 18 did not sign up for photography , this must mean these students are only studying Ceramics)
Now, lets look at our statements
1. 12 did not sign up for ceramics. This means these students have signed up for only Photography.
Now we know x= 12, y=18. Putting this in equation 1 we get the value of our z which is what is required.
2. 42 have signed up for ceramics. This number includes students who have signed up for only ceramics (y) and studnets who have signed up for both photography and ceramics(z). So y+z=42. Putting 18 as the value of y which is already given to us. we can calculate z . Again that is what we need to find out.
P.S. This is an easy question and I have calculated the answer using a Venn Diagram since it is much more suitable and simpler way to find the solution to this question. It is to explain the solution that I have written so much theory.
Lets assume that number of students enrolled in
Only Photography is x
Only Ceramics is y
and both is z
Now, we have been given that x+y+z=54 ---------(1)
And also, that y=18 ( how? out of 54 students 18 did not sign up for photography , this must mean these students are only studying Ceramics)
Now, lets look at our statements
1. 12 did not sign up for ceramics. This means these students have signed up for only Photography.
Now we know x= 12, y=18. Putting this in equation 1 we get the value of our z which is what is required.
2. 42 have signed up for ceramics. This number includes students who have signed up for only ceramics (y) and studnets who have signed up for both photography and ceramics(z). So y+z=42. Putting 18 as the value of y which is already given to us. we can calculate z . Again that is what we need to find out.
P.S. This is an easy question and I have calculated the answer using a Venn Diagram since it is much more suitable and simpler way to find the solution to this question. It is to explain the solution that I have written so much theory.
07 Jul 2026, 16:14
Kudos
Bookmarks
let
x-> photogarphy only
z-> ceramics only
y-> both
Given:
x+y+z=54
z=18
statement 1: ==> x=12 we can get y from the equations above
statement 2: ==> y+z=42, we can get y by substituting z=18
hence either statement is sufficient
x-> photogarphy only
z-> ceramics only
y-> both
Given:
x+y+z=54
z=18
statement 1: ==> x=12 we can get y from the equations above
statement 2: ==> y+z=42, we can get y by substituting z=18
hence either statement is sufficient
Bunuel
07 Jul 2026, 17:15
Kudos
Bookmarks
from statement 1 we get only photography participants, thus 54 - (18+12) gives us who signed up for both.
From statement 2 we get total ceramics = only ceramic + both. 42= 18 + x
From statement 2 we get total ceramics = only ceramic + both. 42= 18 + x
Bunuel
