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08 Jul 2026, 08:00
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
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Question Stats:
78% (02:16) correct
22%
(02:58)
wrong
based on 366
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Three buses leave Riverton and travel along the same route toward Lakeview. Bus 1 leaves first and travels at a constant speed of 50 km/h. Bus 2 leaves Riverton 6 hours after Bus 1 and travels at a constant speed of 80 km/h. Bus 3 also leaves Riverton after Bus 1 and travels at a constant speed of 100 km/h. If Bus 2 and Bus 3 catch up to Bus 1 at the same time, how many hours after Bus 1 leaves does Bus 3 leave?
A. 2
B. 6
C. 8
D. 10
E. 16
A. 2
B. 6
C. 8
D. 10
E. 16
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⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.
M46-36
08 Jul 2026, 09:00
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GMAT Club Official Solution:
Three buses leave Riverton and travel along the same route toward Lakeview. Bus 1 leaves first and travels at a constant speed of 50 km/h. Bus 2 leaves Riverton 6 hours after Bus 1 and travels at a constant speed of 80 km/h. Bus 3 also leaves Riverton after Bus 1 and travels at a constant speed of 100 km/h. If Bus 2 and Bus 3 catch up to Bus 1 at the same time, how many hours after Bus 1 leaves does Bus 3 leave?
A. 2
B. 6
C. 8
D. 10
E. 16
Bus 2 leaves 6 hours after Bus 1, so by the time Bus 2 starts, Bus 1 has traveled 6 * 50 = 300 km. Thus, Bus 1 has a 300 km lead.
To catch Bus 1, Bus 2 needs:
time = distance/relative speed = 300/(80 - 50) = 10 hours
So Bus 2 catches Bus 1 6 + 10 = 16 hours after Bus 1 leaves.
In 16 hours, Bus 1 travels 16 * 50 = 800 km.
Since Bus 3 catches Bus 1 at the same time, Bus 3 must also travel 800 km before catching Bus 1.
At 100 km/h, Bus 3 needs 800/100 = 8 hours
Therefore, Bus 3 must have left 16 - 8 = 8 hours after Bus 1 left.
Answer: C.
Three buses leave Riverton and travel along the same route toward Lakeview. Bus 1 leaves first and travels at a constant speed of 50 km/h. Bus 2 leaves Riverton 6 hours after Bus 1 and travels at a constant speed of 80 km/h. Bus 3 also leaves Riverton after Bus 1 and travels at a constant speed of 100 km/h. If Bus 2 and Bus 3 catch up to Bus 1 at the same time, how many hours after Bus 1 leaves does Bus 3 leave?
A. 2
B. 6
C. 8
D. 10
E. 16
Bus 2 leaves 6 hours after Bus 1, so by the time Bus 2 starts, Bus 1 has traveled 6 * 50 = 300 km. Thus, Bus 1 has a 300 km lead.
To catch Bus 1, Bus 2 needs:
time = distance/relative speed = 300/(80 - 50) = 10 hours
So Bus 2 catches Bus 1 6 + 10 = 16 hours after Bus 1 leaves.
In 16 hours, Bus 1 travels 16 * 50 = 800 km.
Since Bus 3 catches Bus 1 at the same time, Bus 3 must also travel 800 km before catching Bus 1.
At 100 km/h, Bus 3 needs 800/100 = 8 hours
Therefore, Bus 3 must have left 16 - 8 = 8 hours after Bus 1 left.
Answer: C.
General Discussion
ankushsambare
Joined: 13 Jun 2022
Last visit: 01 Sep 2026
Posts: 310
Given Kudos: 227
Location: India
Schools: ISB '27 Wharton '26 INSEAD Aug '26
GPA: 2.4
Products:
08 Jul 2026, 08:06
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Let meeting time be t hrs
Bus 1: Distance = 50t
Bus 2: 80(t-6) = 50t
30t=480
t=16
Let bus 3 leave after x hrs
100(16-x) = 50*16
1600-100x = 800
100x = 800
x = 8
Answer: C
Bus 1: Distance = 50t
Bus 2: 80(t-6) = 50t
30t=480
t=16
Let bus 3 leave after x hrs
100(16-x) = 50*16
1600-100x = 800
100x = 800
x = 8
Answer: C
