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Both = 160
Cardio only = 80
Swim only = 5N
Neither = N
Total = 420

160 + 80 +5N + N = 420
240 +6N = 420
N = 30

Answer: (A) 30
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Let, the number who met the mark for neither activity be "x"
For every member, who met the mark for neither activity, 5 met the mark for swimming, meaning 5x.
Lets create the equation
Cardio only + swim only + neither + both cardio and swim = 420
80 + 5x + x + 160 = 420
6x = 180
x = 30
Answer: 30 (A)
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let the number of members who met the mark for neither activity be x

both swimming and cardio=160
cardio only=80
swimming only=5x
neither=x



since the total is 420:
160+80+5x+x=420
240+6x=420
6x=180
x=30



Bunuel
A recreation center surveyed 420 members about two activities: swimming and cardio-machine workouts. Of the members surveyed, 160 met a 2-hour-per-week mark for both activities, 80 met the mark for cardio-machine workouts but not for swimming, and for every member who met the mark for neither activity, 5 met the mark for swimming but not for cardio-machine workouts. How many of the 420 members met the 2-hour-per-week mark for neither activity?

A. 30
B. 80
C. 150
D. 180
E. 260


 


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Ans choice A: It's a Venn-diagram problem between 2 events Swimming (s) and Cardio (c).
Given : Total members = 420 ; s&c = 160 ; c=80 ; let neither of s&c = x then s= 5x
The equation becomes: 420= 5x + 160 + 80 + x
which gives, x=30
Bunuel
A recreation center surveyed 420 members about two activities: swimming and cardio-machine workouts. Of the members surveyed, 160 met a 2-hour-per-week mark for both activities, 80 met the mark for cardio-machine workouts but not for swimming, and for every member who met the mark for neither activity, 5 met the mark for swimming but not for cardio-machine workouts. How many of the 420 members met the 2-hour-per-week mark for neither activity?

A. 30
B. 80
C. 150
D. 180
E. 260


 


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A - 30

The four groups cover all 420 members. Both cardio only, swim onl and neither.

Both = 160, cardio only = 80, that leaves swim only + neither = 420 - 160 - 80 = 180

Let neither = n. Swim only is 5n, so n + 5n = 180, therefore 6n = 180, n = 30
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S S bar
C16080
C bar 5x x

160+80=240
Subtracting 240 from total 420.
420-240=180

6x=180, therefore x = 30. also S bar, C bar is x = 30, answer A
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Let neither=x
swimming only=5x

160+80+5x+x=420
240+6x=420
6x=180
x=30
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SO if you will see the venn diagram in the image:
we get the equation as
5x + x + 160 + 80 = 420
X = 30
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Given,
Cardio only, C = 80
Swimming only = 5x
Neither = x
Both activities, B = 160
Total members= 420

Equation,

160 + 80 + 5x + x = 420
x = 180/60
x = 30

Answer : A (30)


Bunuel
A recreation center surveyed 420 members about two activities: swimming and cardio-machine workouts. Of the members surveyed, 160 met a 2-hour-per-week mark for both activities, 80 met the mark for cardio-machine workouts but not for swimming, and for every member who met the mark for neither activity, 5 met the mark for swimming but not for cardio-machine workouts. How many of the 420 members met the 2-hour-per-week mark for neither activity?

A. 30
B. 80
C. 150
D. 180
E. 260


 


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Let's solve this using tabular format
CardioNot CardioTotal
Swimming 1605x
Not Swimming 80x
Total240180420

6x == 180
Therefore x == 30

Answer: A
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Bunuel
A recreation center surveyed 420 members about two activities: swimming and cardio-machine workouts. Of the members surveyed, 160 met a 2-hour-per-week mark for both activities, 80 met the mark for cardio-machine workouts but not for swimming, and for every member who met the mark for neither activity, 5 met the mark for swimming but not for cardio-machine workouts. How many of the 420 members met the 2-hour-per-week mark for neither activity?

A. 30
B. 80
C. 150
D. 180
E. 260


 


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Option A total = both + neither + only swim + only cardio. 1x (neither)= 5x(swim)
420 = 160 + n + s + 80. 6x = 420-240 ....... -> x = 30. x is neither so 150 only swim and 30 neither
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The trick in this question is interesting and I couldn't figure it out initially. It's all about how the sets itself are organized. I would recommend spending some time looking into this question to really figure out what the sets are about and arrange them into a TABULAR MATRIX to solve the problem effectively.

First the order of sets:

Swim >= 2 Hours/Wk - Swimmers who meet the mark
Swim Not >=2 Hours/Wk - Swimmers who do not meet the mark

Second Column:

Cardio Machine >= 2 Hours/Wk - Cardio who meet the mark
Cardio Machine Not >= 2 Hours /Wk Cardio who do not meet the mark

Cardio >=2 HoursCardio Not >= 2 Hours
Swim >= 2 Hours1605x
Swim Not >= 2 Hours80x

Total = 420

So we need to solve for 'x', i.e., How many of the 420 members do not meet the mark in either category:

Hence, we can infer that the sum of all the above will be equal to 420, since everyone is accounted for in the Table above. So solving the equation we have:

160 + 80 + 5x + x = 420
6x = 240
x = 30

Hence the answer is 'A'
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420 = only swimming + 80+160 +x
= 5x + 240+x
180 = 6x

x = 30
neither acivity = 30
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Bunuel
A recreation center surveyed 420 members about two activities: swimming and cardio-machine workouts. Of the members surveyed, 160 met a 2-hour-per-week mark for both activities, 80 met the mark for cardio-machine workouts but not for swimming, and for every member who met the mark for neither activity, 5 met the mark for swimming but not for cardio-machine workouts. How many of the 420 members met the 2-hour-per-week mark for neither activity?

A. 30
B. 80
C. 150
D. 180
E. 260


 


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A

Neither + both+ only s + only c = 420

Neither = x
Only Swimming = 5 x

X+5x+160+80= 420

X = 30
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SS'Total
C16080240
C'5xx180
Total160+5x80+x420

we are told that for every 1 person in neither category, 5 met the mark for only swimming.
so say neither= 5
so only swimming = 5x

find= X

160+5x+80+x = 420
6x = 180
x = 30

choice A
Bunuel
A recreation center surveyed 420 members about two activities: swimming and cardio-machine workouts. Of the members surveyed, 160 met a 2-hour-per-week mark for both activities, 80 met the mark for cardio-machine workouts but not for swimming, and for every member who met the mark for neither activity, 5 met the mark for swimming but not for cardio-machine workouts. How many of the 420 members met the 2-hour-per-week mark for neither activity?

A. 30
B. 80
C. 150
D. 180
E. 260


 


This question was provided by GMAT Club
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Cardio: C
Swimming: S

Total: C+S plus Only C, Not S plus Only S, Not C plus Neither CS = 420
C+S = 160
Only C, Not S = 80

Only S, Not C plus Neither CS = 420 - (160+80) = 420-240=180

For every neither CS, 5 Only S, Not C reflected with this
x + 5x = 180
6x = 180
x = 30

So the neither activity = x = 30 (A)

Bunuel
A recreation center surveyed 420 members about two activities: swimming and cardio-machine workouts. Of the members surveyed, 160 met a 2-hour-per-week mark for both activities, 80 met the mark for cardio-machine workouts but not for swimming, and for every member who met the mark for neither activity, 5 met the mark for swimming but not for cardio-machine workouts. How many of the 420 members met the 2-hour-per-week mark for neither activity?

A. 30
B. 80
C. 150
D. 180
E. 260


 


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____________C_________NC_________Total
S_________ 160 _______ 5x _________
NS________ 80 ________ x __________
T_________ 240 _______ 6x __________420

240+6x= 420
6x=420-240=180
x=180/6=30

A. 30
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