We are given that:
Maya does 25% of the work, Felix does 50% and hence Nora does the rest i.e. 25%
Let the time taken by Maya, Felix and Nora be m, f and n respectively. And let their respective contant rates of work be M, F and N
We are also given that n = 2 hours and Maya accounts for half of the total time (m+f+n)
Thus, we know
m = (1/2)*(m+f+n) ==> 2m = m+f+n ==> m = f+n ==> m = f+2
Now, what we need to find is the time that Maya and Felix would take to complete the mural if they work on it together, simultaneously and at their constant work rates.
Thus, the rate of work will be a sum of their individual rates i.e M+F and the time taken will simply be 1/(M+F)
By the rate formula, we know that R = Work/time
We are given that,
M = 0.25/m = = 0.25/(f+2)
F = 0.5/f
Thus, we can see that if using the statements, we can find the value of f, we should be able to calculate the time taken by Maya and Felix
Statement 1: Felix worked for 4 hours
We are directly given f=4. Thus, this statement should be sufficient. We can eliminate B, C and E.
Statement 2: Total time spent by Maya and Nora is twice that of Felix
Thus, m+n = 2f
But we know, m = f+2 and n = 2
Thus, f + 2 + 2 = 2f
f = 4
Thus, this statement is also sufficient. So we can eliminate A.
Thus D is the correct answer choice