Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Aug 2610:00 AM EDT
-11:59 PM EDT
Save up to $1,000 on select GMAT prep now. This Fall, achieve your most ambitious goals with millions of student success stories behind you.
Aug 2710:00 AM EDT
-11:00 AM EDT
We’ve worked incredibly hard to build TTP into the best test prep experience possible, and it would mean a lot to us to win Newsweek’s 2026 Readers’ Choice Award for Best Test Prep. If TTP has helped you, we’d be incredibly grateful for your vote.
Aug 3110:00 AM PDT
-11:00 AM EDT
Top Scores Start with a Elite Online Prep Course. Enroll for 6 months of access to over 400 hours of GMAT video lessons AND 715+ Score Guarantee!
Sep 0212:30 AM EDT
-01:30 AM EDT
Thought your job leaves no time for GMAT prep? After multiple GMAT attempts and a demanding consulting job, Kshitij improved to 695 in under 2 months. Learn the mindset shifts, study strategy, and execution changes that made the breakthrough possible.
Sep 0208:00 PM PDT
-09:00 PM PDT
Video explanations + diagnosis of 10 weakest areas + 150+ short videos + study plan!
Sep 0301:30 AM EDT
-02:30 AM EDT
At one point, she believed GMAT wasn’t for her. After scoring 595, self-doubt crept in and she questioned her potential. But instead of quitting, she made the right strategic changes. The result? A remarkable comeback to 695. Check out how Saakshi did it.
Sep 0907:00 AM PDT
-10:00 AM PDT
Meet AdComs and explore top Master’s programs - MiM, MiF, MSc, MSBA and more. - Application Fee Waivers - Free 1-Week of GMAT Club Tests: - Master's Application Toolkit - Grand Prize Giveaway
ajain31
Joined: 09 Nov 2024
Last visit: 31 Aug 2026
Posts: 69
Given Kudos: 68
Location: United Kingdom
Schools: Wharton '27 Stanford '27 HBS '27 CBS '27
GPA: 71%
15 Jul 2026, 15:50
Kudos
Bookmarks
write down the first 11 primes, 2,3,5,7,11,13,17,19,23,29,31
range is largest to the smallest = 17-5,19-7,23-11,29-17,31-19
now you have to consider the numbers in between, so
5,17 has 7,11,13, and total 4 cards are drawn so, ways to choose is 3 chose 2 = 3
you can do this with other 4 combos and get a total of 11
total number of ways to draw 4 slips from 11 is 11 chose 4 = 330
P = 11/330 = 1/30 final answer
range is largest to the smallest = 17-5,19-7,23-11,29-17,31-19
now you have to consider the numbers in between, so
5,17 has 7,11,13, and total 4 cards are drawn so, ways to choose is 3 chose 2 = 3
you can do this with other 4 combos and get a total of 11
total number of ways to draw 4 slips from 11 is 11 chose 4 = 330
P = 11/330 = 1/30 final answer
Posts: 33
15 Jul 2026, 16:46
Kudos
Bookmarks
First 11 prime numbers: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31
For the set of four numbers picked, the highest number has to be the lowest number+12 and it also has to be a prime number.
Fixing the possible pairs of highest and lowest both present in the set:
5, 17, two of the three numbers in between (total 3C2=3 combinations)
7, 19, two of the three numbers in between (total 3C2=3 combinations)
11, 23, two of the three numbers in between (total 3C2=3 combinations)
17, 29, two numbers in between (total 2C2=1 combination)
19, 31, two numbers in between (total 2C2=1 combination)
Total number of valid possibilities = (3+3+3+1+1)*(4!) [as the sequence of picking may be different] =11*24
Total number of possibilities=11P4=11*10*9*8
Desired probability=(11*24)/(11*10*9*8)=1/30
For the set of four numbers picked, the highest number has to be the lowest number+12 and it also has to be a prime number.
Fixing the possible pairs of highest and lowest both present in the set:
5, 17, two of the three numbers in between (total 3C2=3 combinations)
7, 19, two of the three numbers in between (total 3C2=3 combinations)
11, 23, two of the three numbers in between (total 3C2=3 combinations)
17, 29, two numbers in between (total 2C2=1 combination)
19, 31, two numbers in between (total 2C2=1 combination)
Total number of valid possibilities = (3+3+3+1+1)*(4!) [as the sequence of picking may be different] =11*24
Total number of possibilities=11P4=11*10*9*8
Desired probability=(11*24)/(11*10*9*8)=1/30
15 Jul 2026, 17:47
Kudos
Bookmarks
total number of outcomes= (11*10*9*8)/ (4*3*2*1)=330
prime number pairs with the range of 12 , and 2 or more prime numbers between them:- (5, 17), (7, 19), (11, 23), (17, 29), (19,31)
number of favorable outcomes = no. of ways to select 5* no.of ways to select 17* no. of ways to select 2 out of 3 numbers
thus we get for (5,17) = 1*1*3
(7,19)= 1*1*3
(11,23)= 1*1*3
(17,29)= 1*1*1
(19,31)= 1*1*1
favorable outcomes= 11
probabitlity= 11/330=1/30
prime number pairs with the range of 12 , and 2 or more prime numbers between them:- (5, 17), (7, 19), (11, 23), (17, 29), (19,31)
number of favorable outcomes = no. of ways to select 5* no.of ways to select 17* no. of ways to select 2 out of 3 numbers
thus we get for (5,17) = 1*1*3
(7,19)= 1*1*3
(11,23)= 1*1*3
(17,29)= 1*1*1
(19,31)= 1*1*1
favorable outcomes= 11
probabitlity= 11/330=1/30
Bunuel
