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m + w + c = 240

we know ....
m = w + 20
m + w = c + 20

rearranging....
m+m-20+2m-40 = 240

m = 75.. OA is B
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m+(m-20)+(m+m-20-20)=240

4m=300, so m=75

C
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TheRob
A picnic attracts 240 persons. There are 20 more men than women, and 20 more adults than children. How many men are at this picnic?

A) 240
B) 75
C) 110
D) 130
E) 200

Adult + Children = 240
Let, Children = y
then, Adult = y+20
i.e. y+(y+20) = 240
i.e. y = 110
i.e. Adult = 110+20 = 130

Adults include only Men and Women

i.e. Men + Women = 130

Let women, W = x
then Men, M = x+20

i.e. x+(x+20) = 2x+20 = 130
i.e. x = 55

i.e. Men, M = 55+20 = 75

Answer: Option B
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240=M+W+C
M=W+20
C=M+W-20
C=W+20+W-20
C=2W

now
240=W+20+W+2W
220=4W
W=55
M=55+20
M=75
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TheRob
A picnic attracts 240 persons. There are 20 more men than women, and 20 more adults than children. How many men are at this picnic?

A) 240
B) 75
C) 110
D) 130
E) 200

240 = Adults+ Children

240 = ( Children+20 )+ Children

220 = 2 (Children )

Children = 110
Adults = 130

Now, it is given
Quote:
There are 20 more men than women

Adults = Men + Women

130 = Men + Women

130 = (Women + 20 )+ Women

110 = 2 ( Women )

Women = 55

So, Men = Women + 20

Or, Men = 55 + 20

So, Men = 75

Answer is definitely (B)
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TheRob
A picnic attracts 240 persons. There are 20 more men than women, and 20 more adults than children. How many men are at this picnic?

A) 240
B) 75
C) 110
D) 130
E) 200

# OF MEN W+20
# OF WOMEN W

# OF CHILDREN C
# OF ADULTS C+20

C+C+20 = 240

2C+20=240

# OF CHILDREN = 110

# OF ADULTS = 240-110 = 130

W+20+W = 130

2W+20=130

2W =110

# OF WOMAN = 55

# OF MEN = 55+20 = 75

:)
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Maybe I am being picky, but can't children be counted as men or women? Or those terms are exclusively used for adults?
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Let # adults = A

Adults are composed of Men (M) and Women (W)

Let # children = C

A + C = 240

“20 more adults than children”

A = 20 + C ——> substitute above

(20 + C) + C = 240

C = 110

A = 130

Out of the adults, “there are 20 more men than women”

M + W = A = 130

M = 20 + W ——-> substitute above

(20 + W) + W = 130

W = 55

M = 55 + 20 = 75


M = # of Men = 75 — is the answer

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Given: A picnic attracts 240 persons. There are 20 more men than women, and 20 more adults than children.

Asked: How many men are at this picnic?

Let men, women and children at the picnic be m, w & c respectively.

A picnic attracts 240 persons.
m + w + c = 240

There are 20 more men than women
m = 20 + w

There are 20 more adults than children.
m + w = 20 + c

20 + c + c = 240
c = 110

m + w = 20 + 2w = 130
w = 55

m = 20 + 55 = 75

IMO B
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A picnic attracts 240 persons. There are 20 more men than women, and 20 more adults than children. How many men are at this picnic?

In this problem. There are 4 Variables

"M" for Men
"W" for Women
"A" for Adult
"C" for Children

Lets convert the sentences into algebraic form

1. There are 20 more men than women
i.e. M=W+20 (or) W=M-20


2. There are 20 more adults than children

here adults indirectly means Men & Women that means A=M+W

i.e A=C+20 (or) C=A-20
hence C=M+W-20
Substitute (W=M-20)
C=M+M-20-20
C=2M-40

3. Total no. of people in park is 240
i.e. M+W+C=240

M+M-20+2M-40=240

4M-60=240

4M=300

M=300/4=75

M=75
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