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14 Apr 2025, 00:30
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B
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Difficulty:
95%
(hard)
Question Stats:
42% (02:20) correct
58%
(02:28)
wrong
based on 69
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Train A leaves New York and is heading towards Boston at a constant speed, at the same time train B leaves Boston and is traveling to New York in the opposite direction on a parallel track at a constant speed. Train A is traveling faster than train B, and the distance between New York and Boston is 140 miles. When train A reaches Boston, how far is train B from the point at which the two trains passed each other?
(1) Train A is traveling 15 miles per hour faster than train B.
(2) Train B is traveling at a speed that is one-fourth less than that of Train A’s speed.
(1) Train A is traveling 15 miles per hour faster than train B.
(2) Train B is traveling at a speed that is one-fourth less than that of Train A’s speed.
14 Apr 2025, 10:33
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Simple but time consuming problem
Q: Total Distance: 140, After trains cross each other, How much B travelled till the A reaches destination.
Lets say they cross each other at time t, which is equal to
\(t= \frac{140}{(Sa+Sb)}\)
T required to A reach destination =>\(T=\frac{140}{(Sa)}\)
Distance travelled by B = Sb* (T-t) =>
\(D = Sb* [(\frac{140}{Sa})- (\frac{140}{(Sa+Sb)})]\). (3 unknowns)
S1 => Sa= Sb+15 ( 3 unknowns two equation) Insufficient ( Eliminate A & D)
S2 => Sb= (3/4)* Sa ( 3 unknowns two equation but if you put Sa = 4/3Sb in equation, Sb will cancel out, as we it will come out Common from denominator) Sufficient
(B is the answer)
TIP: Whenever there is a relationship in absolute fractions be aware that the fraction might cancel out and you can get the answer. In case of relation in addition or substation, it is not possible unless all terms have common unknown.
Q: Total Distance: 140, After trains cross each other, How much B travelled till the A reaches destination.
Lets say they cross each other at time t, which is equal to
\(t= \frac{140}{(Sa+Sb)}\)
T required to A reach destination =>\(T=\frac{140}{(Sa)}\)
Distance travelled by B = Sb* (T-t) =>
\(D = Sb* [(\frac{140}{Sa})- (\frac{140}{(Sa+Sb)})]\). (3 unknowns)
S1 => Sa= Sb+15 ( 3 unknowns two equation) Insufficient ( Eliminate A & D)
S2 => Sb= (3/4)* Sa ( 3 unknowns two equation but if you put Sa = 4/3Sb in equation, Sb will cancel out, as we it will come out Common from denominator) Sufficient
(B is the answer)
TIP: Whenever there is a relationship in absolute fractions be aware that the fraction might cancel out and you can get the answer. In case of relation in addition or substation, it is not possible unless all terms have common unknown.
14 Apr 2025, 12:09
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Bunuel
Distance between NY and Boston is 140 miles and trains A and B leave NY and Boston respectively.
To find: how far is train B after both trains have met.
Statement 1:
(1) Train A is traveling 15 miles per hour faster than train B.
This is not sufficient to calculate the individual speeds or the time of meeting. Hence , Insufficient
Statement 2:
(2) Train B is traveling at a speed that is one-fourth less than that of Train A’s speed.
Sb = (1-1/4) Sa
Sb : Sa = 3:4
two trains travelling opposite to each other on a parallel track, and both have started at the same time. Relative speed = 3+4 = 7
time of meet = 140/7 = 20 hrs.
distance travelled by Train A in 20 hrs = 20*4 = 80 miles.
distance travelled by Train B in 20 hrs = 20*3 = 60 miles.
train A covers 60 miles in 60/4 = 15 hrs.
in the same 15 hrs, train B covers 15*3 = 45 miles.
so, the distance of train B from point of meet is 45 miles. HENCE, SUFFICIENT.
OPTION B
