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03 Dec 2020, 12:00
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Difficulty:
35%
(medium)
Question Stats:
69% (01:58) correct
31%
(01:31)
wrong
based on 51
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Two boats leave the same dock at the same time, one traveling due west at 8 miles per hour and the other due north at 15 miles per hour. How many miles apart are the boats after three hours?
(A) 17
(B) 39
(C) 51
(D) 69
(E) 75
(A) 17
(B) 39
(C) 51
(D) 69
(E) 75
03 Dec 2020, 12:15
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One boat is traveling Northwards at 15 miles per hour. The other one Westwards at 8 miles per hour.
In 3 hours, the northern boat has covered 45 miles and the western boat has covered 24 miles. So the distance between them is the hypotenuse of the two directions. We can reduce the values to 15 and 8 while calculating, resulting 17 as the end result. Hence, the final result is 51(17*3).
Answer C is the correct choice.
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In 3 hours, the northern boat has covered 45 miles and the western boat has covered 24 miles. So the distance between them is the hypotenuse of the two directions. We can reduce the values to 15 and 8 while calculating, resulting 17 as the end result. Hence, the final result is 51(17*3).
Answer C is the correct choice.
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ananya3
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Schools: Fuqua '24 Haas '24 ISB '23 Johnson '24 Kelley '24 Kenan-Flagler '24 McDonough '24 NUS Ross '24 Tepper '24 Tuck '24 Rotman '24 (A)
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03 Dec 2020, 20:01
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IMO C
the 2 ships travelling north and west will form the two sides of a right angled triangle.
Pythagorean triplet being used (8, 15, 17)
after 3 hours the two sides will be of size: 24 (speed * time = 8*3) and 45(speed * time = 15*3)
=>multiplying the Pythagorean triplet by 3 (8*3, 15*3, 17*3)
=> distance between the boats = 17*3 = 51
the 2 ships travelling north and west will form the two sides of a right angled triangle.
Pythagorean triplet being used (8, 15, 17)
after 3 hours the two sides will be of size: 24 (speed * time = 8*3) and 45(speed * time = 15*3)
=>multiplying the Pythagorean triplet by 3 (8*3, 15*3, 17*3)
=> distance between the boats = 17*3 = 51
