Last visit was: 17 Jul 2024, 11:38 It is currently 17 Jul 2024, 11:38
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
Math Expert
Joined: 02 Sep 2009
Posts: 94383
Own Kudos [?]: 641737 [20]
Given Kudos: 85693
Send PM
Most Helpful Reply
RC & DI Moderator
Joined: 02 Aug 2009
Status:Math and DI Expert
Posts: 11474
Own Kudos [?]: 34400 [12]
Given Kudos: 322
Send PM
General Discussion
Retired Moderator
Joined: 19 Oct 2018
Posts: 1868
Own Kudos [?]: 6648 [2]
Given Kudos: 705
Location: India
Send PM
RC & DI Moderator
Joined: 02 Aug 2009
Status:Math and DI Expert
Posts: 11474
Own Kudos [?]: 34400 [0]
Given Kudos: 322
Send PM
Re: Two buses, A and B, are going from city P to city Q and back without a [#permalink]
Expert Reply
nick1816 wrote:
For each meeting, Both have to travel 2*1400 = 2800Km combined

Time taken to meet for the 22nd time = 22*2800/50 = 1232 hrs

Distance travelled by bus A in 1232hrs = 1232*50= 1400*44 = 1400*even number

Hence bus A is at point P at the 22nd meeting; Hence, distance of bus A from Q is 1400m.



Bunuel wrote:
Two buses, A and B, are going from city P to city Q and back without a break. Bus A starts from city P and is moving at constant speed of 50km/h, bus B also starts from city P and is moving at constant speed of 20km/h. If the distance between the cities is 1,400 km, how far will bus A be from city Q when the buses meet for the 22nd time?

A. 400 km
B. 600 km
C. 1,000 km
D. 1,200 km
E. 1,400 km


Are You Up For the Challenge: 700 Level Questions



Hi,
You will have to look into the answer again.
It will not be 2800 every time for two reasons.
They start from opposite ends, so, they will meet for the first time after covering 1400m between themselves.
Also there will be times when both are moving in same direction, and at that time they would not have completed a lap between themselves.
Retired Moderator
Joined: 19 Oct 2018
Posts: 1868
Own Kudos [?]: 6648 [4]
Given Kudos: 705
Location: India
Send PM
Re: Two buses, A and B, are going from city P to city Q and back without a [#permalink]
1
Kudos
3
Bookmarks
Sir, they both started from P and i'd read an article during my CAT prep that if the \(v_1 < v_2 < 2v_1\), then they both have to travel 2D combined for their each subsequent meeting. I never tried to get into proof tho lol. Now i'll definitely give a try.




chetan2u wrote:
Hi,
You will have to look into the answer again.
It will not be 2800 every time for two reasons.
They start from opposite ends, so, they will meet for the first time after covering 1400m between themselves.
Also there will be times when both are moving in same direction, and at that time they would not have completed a lap between themselves.
Intern
Intern
Joined: 28 May 2017
Posts: 6
Own Kudos [?]: 5 [1]
Given Kudos: 158
Send PM
Re: Two buses, A and B, are going from city P to city Q and back without a [#permalink]
1
Kudos
Bunuel wrote:
Two buses, A and B, are going from city P to city Q and back without a break. Bus A starts from city P and is moving at constant speed of 50km/h, bus B also starts from city P and is moving at constant speed of 20km/h. If the distance between the cities is 1,400 km, how far will bus A be from city Q when the buses meet for the 22nd time?

A. 400 km
B. 600 km
C. 1,000 km
D. 1,200 km
E. 1,400 km


Are You Up For the Challenge: 700 Level Questions

Everytime A and B meet, they would have traveled a total of 2800 kms combined.
Since the Ratio of Speed of A and B = Ratio of Distance traveled = 5:2, A would travel 2000 kms and B would travel 800 kms everytime they meet.
Now, at the 22nd time, A would have traveled 2000 x 22 = 44,000 kms
At every 2800 kms, A would be at Point P. Therefore, at 42,000 kms, A would be at Point P. For remaining 2000 kms, he would be 2000 - 1400 (distance P to Q) = 600 kms from Point Q.
RC & DI Moderator
Joined: 02 Aug 2009
Status:Math and DI Expert
Posts: 11474
Own Kudos [?]: 34400 [0]
Given Kudos: 322
Send PM
Two buses, A and B, are going from city P to city Q and back without a [#permalink]
Expert Reply
nick1816 wrote:
Sir, they both started from P and i'd read an article during my CAT prep that if the \(v_1 < v_2 < 2v_1\), then they both have to travel 2D combined for their each subsequent meeting. I never tried to get into proof tho lol. Now i'll definitely give a try.




chetan2u wrote:
Hi,
You will have to look into the answer again.
It will not be 2800 every time for two reasons.
They start from opposite ends, so, they will meet for the first time after covering 1400m between themselves.
Also there will be times when both are moving in same direction, and at that time they would not have completed a lap between themselves.


Sorry, there was another question which had both starting from opposite ends. But the point remains the same..
You can check on the time they meet for 3rd and 4th time, and you will get the answer.

Yes, when they meet at the same point again, the average distance per meet for all the times they meet during this period would be 2800.
Retired Moderator
Joined: 19 Oct 2018
Posts: 1868
Own Kudos [?]: 6648 [0]
Given Kudos: 705
Location: India
Send PM
Re: Two buses, A and B, are going from city P to city Q and back without a [#permalink]
chetan2u

I agree to you Sir. Actually, i took the value of the speed of slower bus wrong (30). In that case, faster bus never catches the slower one two times in a lap. Hence, for each subsequent meetings, both have to travel 2D combined.

You are absolutely correct about this question. Since velocity of the faster bus is more than two times of the slower one, it will catch the slower one two times in few laps. Hence, for each subsequent meeting, the relative distance travelled is not always equals to 2D.

Thanks
Manager
Manager
Joined: 09 Nov 2015
Posts: 201
Own Kudos [?]: 335 [0]
Given Kudos: 96
Send PM
Re: Two buses, A and B, are going from city P to city Q and back without a [#permalink]
After they set off from P, bus A (BA) doesn’t meet bus B (BB) on its (BA’s) 1st lap since it is faster than BB and always stays ahead until it reaches Q and turns back for its 2nd lap. On each of its subsequent laps BA meets BB once because: (a) it is impossible for BA to avoid meeting BB as BB will always be somewhere on the road when BA begins a fresh lap so BA will either overtake BB or cross it and (b) it is also not possible for BA to have more than one meeting with BB in a single lap because, after one meeting, BA will be moving away from BB until it completes the lap. This sequence (BA meeting BB once during each of its laps except the first) continues for (BA’s) 10 laps on completion of which both buses are back at P (BB having completed 4 laps in the same time) and the cycle begins again. So, during each cycle (BA’s 10 laps and BB’s 4), there are 9 (10 – 1) meetings. First two cycles and 18 meetings later both buses are back at P and the third cycle begins. For reasons explained earlier, there is no meeting on BA’s 1st lap of the fresh cycle and one meeting during each of its subsequent laps. So the 4th meeting of the third cycle (or 22nd meeting from the beginning) will take place on BA’s 5th lap of the third cycle. We have to determine exactly where on the PQ road this meeting takes place:
After the end of its 4th lap BA is at city P having completed 4 laps (4L). During the same time, BB will have completed 4L*(2/5) = (8/5)L = 1.6L. That means it has completed one lap (from P to Q), turned around and completed (3/5)th of the distance towards P. So, at this point, BA is at P and BB is (2/5)L from P. Since the two buses are moving towards each other and BA:BB=5:2, BA will cover (5/7)th of the separating distance or (5/7)*(2/5)L=(2/7)L=(2/7)*1400km=400km. Since BA starts out from P, it meets BB 1000kms (1400 – 400) from city Q.
ANS: C

P.S. Since this answer is different from the OA and other answers I was afraid that my reasoning was flawed or I might have overlooked something so I worked out, step by step, the location of each meeting for an entire cycle but the answer was the same. I would request Bunuel, chetan2u and nick1816 to kindly look into my solution and point out if and where I might have gone wrong.
User avatar
Non-Human User
Joined: 09 Sep 2013
Posts: 33999
Own Kudos [?]: 851 [0]
Given Kudos: 0
Send PM
Re: Two buses, A and B, are going from city P to city Q and back without a [#permalink]
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
GMAT Club Bot
Re: Two buses, A and B, are going from city P to city Q and back without a [#permalink]
Moderator:
Math Expert
94383 posts