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Two different teams, X and Y, which have no members in common, will me

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Two different teams, X and Y, which have no members in common, will me  [#permalink]

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New post 07 Jan 2018, 23:03
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71% (01:09) correct 29% (01:07) wrong based on 28 sessions

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Two different teams, X and Y, which have no members in common, will merge to form a new team Z. If the average (arithmetic mean) height of the players on team X is 5 feet 7 inches and the average height of the players on team Y is 5 feet 10 inches, which team has more players?

(1) If a new team, team Z, is formed from teams X and Y it will have an average height of 5 feet 9 inches.
(2) There are 12 players on team X.

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Re: Two different teams, X and Y, which have no members in common, will me  [#permalink]

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New post 08 Jan 2018, 11:43
Bunuel wrote:
Two different teams, X and Y, which have no members in common, will merge to form a new team Z. If the average (arithmetic mean) height of the players on team X is 5 feet 7 inches and the average height of the players on team Y is 5 feet 10 inches, which team has more players?

(1) If a new team, team Z, is formed from teams X and Y it will have an average height of 5 feet 9 inches.
(2) There are 12 players on team X.


(1) We can see that the combined average of team Z (which comprises of members from X and Y) is 5 feet 9 inches, and this value is closer to the average height of team Y (5 feet 10 inches) than it is to the average height of team X (5 feet 7 inches). This means there are more players in team Y than there are in team X. Sufficient.

(2) 12 players in team X, but nothing mentioned about Y, or nothing about combined average. Insufficient.

Hence A answer
Re: Two different teams, X and Y, which have no members in common, will me &nbs [#permalink] 08 Jan 2018, 11:43
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