Two equally sized jugs full of water are each emptied into

Question

Two equally sized jugs full of water are each emptied into two separate unequally sized empty jugs, X and Y. Now, jug X is 1/5 full, while jug Y is 2/3 full. If water is poured from jug X into jug Y until jug Y is filled, what fraction of jug X then contains water?

A. 0
B. 1/15
C. 2/15
D. 1/10
E. 2/10

I have tried solving it using no's...Unable to get the right answer.Can anyone elaborate please?

A. 0
B. 1/15
C. 2/15
D. 1/10
E. 2/10

Bunuel · Accepted Answer

There are equal amounts of water in jars X and Y, say 2L, then: The capacity of jar X is 10L (1/5*10=2L). The capacity of jar Y is 3L (2/3*3=2L). Now, in order jar Y to be full we need to pour 1L from jar X to jar Y, thus there will be 1L of water left in jar X, which is 1/10 of it. Answer: D. Similar question to practice: equal-amount-of-water-were-poured-into-two-empty-jars-of-98962.html?hilit=water

PareshGmat · Answer

Jug X is filled 1/5th = 1/5 x.............. (1)
Jug Y is filled 2/3rd = 2/3 y................(2)

From the condition given, (1) = (2)
So, 1/5x = 2/3y.............................. (3)

To fill the Jug Y completely, additional water required-
= y-2/3y
= 1/3y............................................ (4)

Comparing (3) & (4), we get 1/3y = 1/10 x
So, Answer = D

BrushMyQuant · Answer

Suppose the water in each jug is L liters
CX x (1/5) = L
CX = 5L liters

CX is capacity of X

CY x (2/3) = L
CY = 3L/2 liters

CY is capacity of Y

Now, Y is 3L/2 - L empty = L/2 empty
So, we can put only L/2 water in jug Y from Jug X

Jug X's remaining water = L - L/2 = L/2

Fraction of X which contains water = water / CX
= (L/2)/ 5L
= 1/10

Answer will be D
Hope it helps!

manishtank1988 · Answer

My 2 Cents:

rulingbear · Answer

IMO, I think plugging number is the best approach to this sort of problem, especially for the not so confident test taker. Bunuel has given a variety of the this in a post above. Here is a similar, but IMO more foolproof approach.

1. Look for a number that is a multiple of all the integers, in the question, i.e 2*3*5 = 30. 
2. Now, take this number as the equal starting volume and the find the capacity of each new jug.
 1/5(X) = 30, X= 150
 2/3(Y) = 30, Y= 45

3. Now take 15 from X to fill Y up. This leaves 15 in X.
 30+15 = 45 ( Fills up Y)
 30-15 = 15 ( Remains in X)

4. Fraction of water remaining in X = 15/150 = 1/10 (D)

SVaidyaraman · Answer

1. Let us take the amount of water emptied as 10 L + 10 L i.e., jug x and jug y contain 10 L each 
2. Jug x is 1/5 full i.e., capacity of jug x is 10*5=50 L
3. Jug y is is 2/3 full i.e., capacity of jug y is 10*3/2=15 L. 
4. Five more liters will make jug y full.
5. After pouring 5 L, water left in jug x is 5 L.
6. Fraction of water contained in jug x is 5/50 = 1/10

Gprabhumir · Answer

Use this simple approach. Don't even need to get into fancy formulae.

\frac{1}{5}X =\frac{2}{3}Y 
Jug Y is two parts full and can accomodate one more part, which means  \frac{1}{2}  of original water.
Jug X is  \frac{1}{5}  full with total original water. Half of it will be poured and half will be left  =\frac{1}{5}*\frac{1}{2} =\frac{1}{10}

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Two equally sized jugs full of water are each emptied into

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