GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 19 Oct 2019, 06:21 GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.  Two prime numbers are considered consecutive if no other prime lies be

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:

Hide Tags

Math Expert V
Joined: 02 Sep 2009
Posts: 58449
Two prime numbers are considered consecutive if no other prime lies be  [#permalink]

Show Tags 00:00

Difficulty:   65% (hard)

Question Stats: 57% (02:18) correct 43% (02:14) wrong based on 109 sessions

HideShow timer Statistics

Two prime numbers are considered consecutive if no other prime lies between them on the number line. If $$p_1$$ and $$p_2$$ are consecutive primes, with $$|p_1 – p_2| > 2$$, what is the smallest possible absolute value of the coefficient of the x term in the distributed form of the expression $$(x – p_1)(x – p_2)$$?

(A) 5
(B) 8
(C) 12
(D) 18
(E) 24

Kudos for a correct solution.

_________________
Manager  B
Joined: 08 Aug 2015
Posts: 55
Re: Two prime numbers are considered consecutive if no other prime lies be  [#permalink]

Show Tags

I didn't really understand the question. Can someone explain it please?

I did however try to get to an answer. For example, the smallest two consecutive prime numbers that have a difference greater than two are 7 and 11. So I guessed that the answer is 12 since its the smallest number that is greater than both the primes - 7 and 11.

(12 - 7)(12 - 11) ??

Sorry if I'm not making any sense. Waiting for the OA...
Intern  Joined: 11 May 2014
Posts: 17
Re: Two prime numbers are considered consecutive if no other prime lies be  [#permalink]

Show Tags

I am also puzzling with this problem. I find no connection between value of x and the end result of the given expression. Is it asking for minimum of both? If so there are 2 answers, 8 and 24, that qualifies with end result of -3.

(8-7)(8-11)=-3
(24-23)(24-27)=-3
Manager  Joined: 10 Aug 2015
Posts: 103
Re: Two prime numbers are considered consecutive if no other prime lies be  [#permalink]

Show Tags

2
Bambaruush wrote:
I am also puzzling with this problem. I find no connection between value of x and the end result of the given expression. Is it asking for minimum of both? If so there are 2 answers, 8 and 24, that qualifies with end result of -3.

(8-7)(8-11)=-3
(24-23)(24-27)=-3

Solution: $$(x-p1)*(x-p2) = x^{2} - (p1 + p2) + p1p2$$
The absolute co-efficient of x is p1+p2. And for this to be minimum and satisfy |p1–p2|>2, p1 and p2 should be 11 and 7.
So,p1+p2 = 18.

Option D
Intern  Joined: 16 Jul 2015
Posts: 2
Concentration: General Management, Finance
GPA: 3.56
Re: Two prime numbers are considered consecutive if no other prime lies be  [#permalink]

Show Tags

1
We know that the set of prime numbers is 2, 3, 5, 7, 11, 13, 17, ...

Statement 1: p1 and p2 are consecutive primes, with |p1–p2|>2
--> the first set of two consecutive primes that qualifies is 7 and 11

Statement 2: smallest possible absolute value of the coefficient of the x term in the distributed form of the expression (x–p1)(x–p2)?
--> distributed form of (x–p1)(x–p2) --> (x-7)(x-11) --> x^2 - 7x - 11x +77 --> x^2 -18x + 77
--> smallest coefficient of the term x is therefore -18
Manager  Joined: 10 Aug 2015
Posts: 103
Re: Two prime numbers are considered consecutive if no other prime lies be  [#permalink]

Show Tags

sanderintelmann wrote:
We know that the set of prime numbers is 2, 3, 5, 7, 11, 13, 17, ...

Statement 1: p1 and p2 are consecutive primes, with |p1–p2|>2
--> the first set of two consecutive primes that qualifies is 7 and 11

Statement 2: smallest possible absolute value of the coefficient of the x term in the distributed form of the expression (x–p1)(x–p2)?
--> distributed form of (x–p1)(x–p2) --> (x-7)(x-11) --> x^2 - 7x - 11x +77 --> x^2 -18x + 77
--> smallest coefficient of the term x is therefore -18

On what basis did you select 7 and 11 as qualified? The criteria of selecting p1 and p2 should be such that the value of p1+ p2 is minimum and |p1–p2|>2.Then only you get the values as 7 and 11. Can you explain me how you got 7 and 11 before getting into 2nd statement.?
Intern  Joined: 16 Jul 2015
Posts: 2
Concentration: General Management, Finance
GPA: 3.56
Re: Two prime numbers are considered consecutive if no other prime lies be  [#permalink]

Show Tags

anudeep133 wrote:
sanderintelmann wrote:
We know that the set of prime numbers is 2, 3, 5, 7, 11, 13, 17, ...

Statement 1: p1 and p2 are consecutive primes, with |p1–p2|>2
--> the first set of two consecutive primes that qualifies is 7 and 11

Statement 2: smallest possible absolute value of the coefficient of the x term in the distributed form of the expression (x–p1)(x–p2)?
--> distributed form of (x–p1)(x–p2) --> (x-7)(x-11) --> x^2 - 7x - 11x +77 --> x^2 -18x + 77
--> smallest coefficient of the term x is therefore -18

On what basis did you select 7 and 11 as qualified? The criteria of selecting p1 and p2 should be such that the value of p1+ p2 is minimum and |p1–p2|>2.Then only you get the values as 7 and 11. Can you explain me how you got 7 and 11 before getting into 2nd statement.?

You're right - you cannot evaluate statement 1 without reference to the constraint of "smallest possible absolute value." I went through the below pairs of primes when choosing 7 and 11. Given we are looking for the smallest possible coefficient of x, 7+11=18 is smaller than 13+17=30.

P1 P2 P1-P2 ABS >2?
2 3 -1 No
3 5 -2 No
5 7 -2 No
7 11 -4 Yes
11 13 -2 No
13 17 -4 Yes
Manager  Joined: 10 Aug 2015
Posts: 103
Re: Two prime numbers are considered consecutive if no other prime lies be  [#permalink]

Show Tags

sanderintelmann wrote:
anudeep133 wrote:
sanderintelmann wrote:
We know that the set of prime numbers is 2, 3, 5, 7, 11, 13, 17, ...

Statement 1: p1 and p2 are consecutive primes, with |p1–p2|>2
--> the first set of two consecutive primes that qualifies is 7 and 11

Statement 2: smallest possible absolute value of the coefficient of the x term in the distributed form of the expression (x–p1)(x–p2)?
--> distributed form of (x–p1)(x–p2) --> (x-7)(x-11) --> x^2 - 7x - 11x +77 --> x^2 -18x + 77
--> smallest coefficient of the term x is therefore -18

On what basis did you select 7 and 11 as qualified? The criteria of selecting p1 and p2 should be such that the value of p1+ p2 is minimum and |p1–p2|>2.Then only you get the values as 7 and 11. Can you explain me how you got 7 and 11 before getting into 2nd statement.?

You're right - you cannot evaluate statement 1 without reference to the constraint of "smallest possible absolute value." I went through the below pairs of primes when choosing 7 and 11. Given we are looking for the smallest possible coefficient of x, 7+11=18 is smaller than 13+17=30.

P1 P2 P1-P2 ABS >2?
2 3 -1 No
3 5 -2 No
5 7 -2 No
7 11 -4 Yes
11 13 -2 No
13 17 -4 Yes

Its all fine then. It seemed to me that you selected 7,11 before statement 2. What you did is correct. Sry to disturb you Intern  B
Joined: 14 Jul 2015
Posts: 21
Location: India
Concentration: International Business, General Management
GMAT 1: 660 Q49 V32 WE: Business Development (Energy and Utilities)
Re: Two prime numbers are considered consecutive if no other prime lies be  [#permalink]

Show Tags

1
(x−p1)∗(x−p2)=x2−(p1+p2)x+p1p2

Value of (p1+p2) will be min. for the min consecutive primes which satisfy |p1-p2|>2

So the min. value p1 & p2 can take = 7, 11

p1+p2= 7+11= 18

Ans. D
Intern  Joined: 12 Nov 2013
Posts: 39
Re: Two prime numbers are considered consecutive if no other prime lies be  [#permalink]

Show Tags

Bunuel wrote:
Two prime numbers are considered consecutive if no other prime lies between them on the number line. If $$p_1$$ and $$p_2$$ are consecutive primes, with $$|p_1 – p_2| > 2$$, what is the smallest possible absolute value of the coefficient of the x term in the distributed form of the expression $$(x – p_1)(x – p_2)$$?

(A) 5
(B) 8
(C) 12
(D) 18
(E) 24

Kudos for a correct solution.

Not sure of the answer. Waiting for Bunuel to post solution
_________________
Kindly support by giving Kudos, if my post helped you!
CEO  D
Status: GMATINSIGHT Tutor
Joined: 08 Jul 2010
Posts: 2978
Location: India
GMAT: INSIGHT
Schools: Darden '21
WE: Education (Education)
Two prime numbers are considered consecutive if no other prime lies be  [#permalink]

Show Tags

2
Bunuel wrote:
Two prime numbers are considered consecutive if no other prime lies between them on the number line. If $$p_1$$ and $$p_2$$ are consecutive primes, with $$|p_1 – p_2| > 2$$, what is the smallest possible absolute value of the coefficient of the x term in the distributed form of the expression $$(x – p_1)(x – p_2)$$?

(A) 5
(B) 8
(C) 12
(D) 18
(E) 24

Kudos for a correct solution.

Let's solve the expression $$(x – p_1)(x – p_2)$$ first

$$(x – p_1)(x – p_2)$$ = $$x^2 - (p_1 + p_2)x + (p_1 * p_2)$$

Now, Co-efficient of x term $$[(p_1 + p_2)x] = (p_1 + p_2)$$

i.e. We need to calculate the Minimum Absolute value of $$(p_1 + p_2)$$ which will be possible for MINIMUM values of both $$p_1$$ & $$p_2$$

But, $$|p_1 – p_2| > 2$$ i.e. we need to find two consecutive SMALLEST Prime numbers which are separated by more than 2

List of Prime Numbers: 2, 3, 5, 7, 11, 13, 17 ...

i.e. $$p_1 = 7$$ and $$p_2 = 11$$

i.e. Minimum Value of $$(p_1 + p_2) = 7+11 = 18$$

_________________
Prosper!!!
GMATinsight
Bhoopendra Singh and Dr.Sushma Jha
e-mail: info@GMATinsight.com I Call us : +91-9999687183 / 9891333772
Online One-on-One Skype based classes and Classroom Coaching in South and West Delhi
http://www.GMATinsight.com/testimonials.html

ACCESS FREE GMAT TESTS HERE:22 ONLINE FREE (FULL LENGTH) GMAT CAT (PRACTICE TESTS) LINK COLLECTION
Senior Manager  P
Joined: 27 Aug 2014
Posts: 339
Location: Netherlands
Concentration: Finance, Strategy
Schools: LBS '22, ISB '21
GPA: 3.9
WE: Analyst (Energy and Utilities)
Re: Two prime numbers are considered consecutive if no other prime lies be  [#permalink]

Show Tags

1
Bunuel wrote:
Two prime numbers are considered consecutive if no other prime lies between them on the number line. If $$p_1$$ and $$p_2$$ are consecutive primes, with $$|p_1 – p_2| > 2$$, what is the smallest possible absolute value of the coefficient of the x term in the distributed form of the expression $$(x – p_1)(x – p_2)$$?

(A) 5
(B) 8
(C) 12
(D) 18
(E) 24

Kudos for a correct solution.

coefficient of x is (p1+p2). the sum of the smallest prime numbers that are consecutive and also with the condition $$|p_1 – p_2| > 2$$
are 7,11

first few primes are 2,3,5,7,11,13,17,19..
out of these 7 and 11 satisfy so
D
Manager  Joined: 29 Jul 2015
Posts: 155
Re: Two prime numbers are considered consecutive if no other prime lies be  [#permalink]

Show Tags

Bunuel wrote:
Two prime numbers are considered consecutive if no other prime lies between them on the number line. If $$p_1$$ and $$p_2$$ are consecutive primes, with $$|p_1 – p_2| > 2$$, what is the smallest possible absolute value of the coefficient of the x term in the distributed form of the expression $$(x – p_1)(x – p_2)$$?

(A) 5
(B) 8
(C) 12
(D) 18
(E) 24

Kudos for a correct solution.

Two prime numbers are considered consecutive if no other prime lies between them.
So the pairs of these prime numbers can be (2,3) (3,5) (5,7) (7,11) and so on
We are also given that difference between two prime numbers should be greater than 2.
Now, we are to find the smallest absolute value of coefficient of x in $$(x – p_1)(x – p_2)$$
Distributed for of this expression will be

$$(x – p_1)(x – p_2)$$ = $$x^2 - p_1x - p_2x + p_1p_2$$ = $$x^2 - (p_1+ p_2)x + p_1p_2$$

the coefficient of x here is $$- (p_1+ p_2)$$
We want smallest possible value of $$|- (p_1+ p_2)|$$ or $$(p_1+ p_2)$$

Our first such set of $$p_1$$ and $$p_2$$ according to the above mentioned condition will be (7,11)
So, smallest possible absolute value of the coefficient of the x term is 7+11 =18

Math Expert V
Joined: 02 Sep 2009
Posts: 58449
Re: Two prime numbers are considered consecutive if no other prime lies be  [#permalink]

Show Tags

Bunuel wrote:
Two prime numbers are considered consecutive if no other prime lies between them on the number line. If $$p_1$$ and $$p_2$$ are consecutive primes, with $$|p_1 – p_2| > 2$$, what is the smallest possible absolute value of the coefficient of the x term in the distributed form of the expression $$(x – p_1)(x – p_2)$$?

(A) 5
(B) 8
(C) 12
(D) 18
(E) 24

Kudos for a correct solution.

MANHATTAN GMAT OFFICIAL SOLUTION:

The question seems forbidding, but start by grabbing onto the most concrete part, which comes at the end. Start with distributing $$(x – p_1)(x – p_2)$$.
$$(x – p_1)(x – p_2) = x^2 – (p_1 + p_2)x + p_1p_2$$

All we care about is the coefficient of the x term, which is $$–(p_1 + p_2)$$. Specifically, we care about the absolute value of this, which is p_1 + p_2, since primes are by definition positive.

So what we are really asked for is the smallest possible value of $$p_1 + p_2$$, under two conditions:

1. These two primes are consecutive, meaning that there’s no other prime between them.
2. $$|p_1 – p_2| > 2$$, meaning that the primes are more than 2 units apart on the number line.

In other words, the question really is “what is the smallest possible sum of two consecutive primes that are more than 2 units apart?”

Now take the first several primes: 2, 3, 5, 7, 11, 13. The first pair of consecutive primes more than 2 units apart is {7, 11}. Their sum is 18.

The correct answer is D.
_________________
GMAT Club Legend  V
Joined: 12 Sep 2015
Posts: 4009
Re: Two prime numbers are considered consecutive if no other prime lies be  [#permalink]

Show Tags

Top Contributor
Bunuel wrote:
Two prime numbers are considered consecutive if no other prime lies between them on the number line. If $$p_1$$ and $$p_2$$ are consecutive primes, with $$|p_1 – p_2| > 2$$, what is the smallest possible absolute value of the coefficient of the x term in the distributed form of the expression $$(x – p_1)(x – p_2)$$?

(A) 5
(B) 8
(C) 12
(D) 18
(E) 24

We're told that p1 and p2 are CONSECUTIVE primes (no primes in between)
We're also told that |p1 – p2| > 2, which means the two primes are MORE THAN 2 units away.
So, for example, the two primes cannot be 3 and 5, since the two primes are 2 units away.

Can two CONSECUTIVE primes be THREE units away?
For the primes to be THREE units away, one prime must be EVEN and the other must be ODD
Since 2 is the only EVEN prime, the smaller prime must be 2, which means the bigger prime must be 5.
HOWEVER, 2 and 5 are not CONSECUTIVE primes, since the prime number 3 lies between 2 and 5
So, we can conclude that two consecutive primes be CANNOT be THREE units away

Can two CONSECUTIVE primes be FOUR units away?
Let's check some primes that are FOUR units away
3 and 7. No good. They are not CONSECUTIVE since the prime number 5 lies between 3 and 7.
5 and 9. No good. 9 isn't prime.
7 and 11. PERFECT! 7 and 11 are prime, and they're consecutive.

So, 7 and 11 are the smallest values for p1 and p2.

What is the smallest possible absolute value of the coefficient of the x term in the distributed form of the expression (x – p1)(x – p2)?
We can say that p1 = 7, and p2 = 11
We get: (x – p1)(x – p2) = (x – 7)(x – 11)
= x² - 11x - 7x + 77
= x² - 18x + 77
The COEFFICIENT of the x term is -18

We want to find the smallest possible ABSOLUTE VALUE of the coefficient of the x term
So, we want |-18|, which equals 18

Cheers,
Brent
_________________ Re: Two prime numbers are considered consecutive if no other prime lies be   [#permalink] 23 Feb 2019, 10:52
Display posts from previous: Sort by

Two prime numbers are considered consecutive if no other prime lies be

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne  