dixitraghav
Two regular pentagons ABCDE and BCFGH have a side BC common. X is the mid point of AE, Y is the mid point of BC and Z is the mid point of GH.
1. If the sides EXA, CYB and GZH are extended, they will intersect at one point.
2. The point of intersection of these sides will be the center of circle passing through points X, Y and Z.
A. Only 1 is correct
B. Only 2 is correct
C. 1 and 2 are both Correct
D. Neither 1 nor 2 is correct
E. Information not sufficient
Source: Self-made
Follow posting guidelines (link in my signatures) especially choosing either PS or DS forum for your questions, make sure to mention the correct the title, complete question, all options, 3 tags (one each for source, difficulty and subtopic) and the official answer. Based on the information given, both the statements should be correct. C is the correct answer.
Statement 1 is clearly visible as the angles between any 2 of the 3 line segments EXA, CYB and GZH is \neq 0 or 180 .
For statement 2, if the above 3 lines are intersecting at the same point, this common point of intersection will become the center of the circle (lets call it 'O'), making OG, OC and OE (or for a smaller circle OZ, OY and OX as the radii) the radii of the circle.
Refer to the attached picture for details.
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