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let distance = x
speed of train 1 ; x/18
speed of train 2 ; x/12
total speed ; 5x/36
total time taken to cross each other ; x+x/5x/36 ; 36*2x/5x ; 14.4 sec
IMO C


jackfr2
Two train of equal length running in opposite direction, pass a pole in 18 and 12
seconds. The trains will cross each other in ?
a. 12.6 seconds
b. 13.5 seconds
c. 14.4 seconds
d. 15.3 seconds
e. 16 seconds

Posted from my mobile device
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Length of one train = LCM (18, 12) = 36
Speed of first train = 36/18 = 2
Speed of second train = 36/12 = 3
Total length (distance) of the two trains = 2(36) = 72
Relative speed = 5
Time to cross each other = 72/5 = 14.4
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jackfr2
Two train of equal length running in opposite direction, pass a pole in 18 and 12
seconds. The trains will cross each other in ?
a. 12.6 seconds
b. 13.5 seconds
c. 14.4 seconds
d. 15.3 seconds
e. 16 seconds

Posted from my mobile device

Given: Two train of equal length running in opposite direction, pass a pole in 18 and 12
seconds.

Asked: The trains will cross each other in ?

Let the length of each train = 36 m

Speed of first train = 2 m/s
Speed of second train = 3 m/s

The trains will cross each other in = 2*36/(2+3) = 72/5 = 14.4 seconds

IMO C
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D=r*18
D=r*12

2D/(d/18+d/12)
2(12*18)/(12+18)
2(216)/(30)
216/15
14.4
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