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MichelleSavina
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A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} Sun Jan 23, 2011 10:31 am
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Q) A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} is defined with given numbers. Now one number is chosen randomly from each of the given set in such a way that the absolute difference between the two numbers is 2. What is the probability that one of the number chosen is 3?


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1/2
(Sorry I don't have the answer choices for the question above.)
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A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} Sun Jan 23, 2011 10:48 am
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MichelleSavina
Q) A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} is defined with given numbers. Now one number is chosen randomly from each of the given set in such a way that the absolute difference between the two numbers is 2. What is the probability that one of the number chosen is 3?


Answer:- 1/2
(Sorry I don't have the answer choices for the question above.)
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Probability=# of favorable outcomes/total # of outcomes;

There are total of 8 (p,q) pairs possible so that the absolute difference between the two numbers to be 2: (1, 3), (2, 4), (3, 5), (3, 1), (4, 6), (4, 2), (5, 7), (5, 3) (first # is chosen from set P and second # is chosen from set Q). 4 pairs contain the number 3 in it, so P=4/8=1/2.
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A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} Sun Dec 11, 2016 8:03 pm
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Q) A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} is defined with given numbers. Now one number is chosen randomly from each of the given set in such a way that the absolute difference between the two numbers is 2. What is the probability that one of the number chosen is 3?


Answer:- 1/2
(Sorry I don't have the answer choices for the question above.)

Probability=# of favorable outcomes/total # of outcomes;

There are total of 8 (p,q) pairs possible so that the absolute difference between the two numbers to be 2: (1, 3), (2, 4), (3, 5), (3, 1), (4, 6), (4, 2), (5, 7), (5, 3) (first # is chosen from set P and second # is chosen from set Q). 4 pairs contain the number 3 in it, so P=4/8=1/2.
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Why not (7,5) (6,4) are taken in total
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A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} Mon Dec 12, 2016 12:10 am
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Q) A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} is defined with given numbers. Now one number is chosen randomly from each of the given set in such a way that the absolute difference between the two numbers is 2. What is the probability that one of the number chosen is 3?


Answer:- 1/2
(Sorry I don't have the answer choices for the question above.)

Probability=# of favorable outcomes/total # of outcomes;

There are total of 8 (p,q) pairs possible so that the absolute difference between the two numbers to be 2: (1, 3), (2, 4), (3, 5), (3, 1), (4, 6), (4, 2), (5, 7), (5, 3) (first # is chosen from set P and second # is chosen from set Q). 4 pairs contain the number 3 in it, so P=4/8=1/2.


Why not (7,5) (6,4) are taken in total
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There is not 7 and there is no 6 in set P.
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A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} Mon Sep 25, 2017 7:13 am
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There are total of 8 (p,q) pairs possible so that the absolute difference between the two numbers to be 2: (1, 3), (2, 4), (3, 5), (3, 1), (4, 6), (4, 2), (5, 7), (5, 3) (first # is chosen from set P and second # is chosen from set Q). 4 pairs contain the number 3 in it, so P=4/8=1/2.[/quote]


Bunuel - according to my inference from the question we are not specifically told to select first no. from set P and the second no. from set Q. Why are we specifically following the order ?
Could u please explain as to how did u extrapolate that first should no. should be taken by Set P and second no. form Set Q
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A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} Mon Sep 25, 2017 7:17 am
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gmatdemolisher1234
There are total of 8 (p,q) pairs possible so that the absolute difference between the two numbers to be 2: (1, 3), (2, 4), (3, 5), (3, 1), (4, 6), (4, 2), (5, 7), (5, 3) (first # is chosen from set P and second # is chosen from set Q). 4 pairs contain the number 3 in it, so P=4/8=1/2.
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Bunuel - according to my inference from the question we are not specifically told to select first no. from set P and the second no. from set Q. Why are we specifically following the order ?
Could u please explain as to how did u extrapolate that first should no. should be taken by Set P and second no. form Set Q[/quote]

It just means that when I list the possible pairs in each pair first # is from set P and second # is from set Q.
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A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} Mon Jan 13, 2020 2:04 pm
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MichelleSavina
Q) A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} is defined with given numbers. Now one number is chosen randomly from each of the given set in such a way that the absolute difference between the two numbers is 2. What is the probability that one of the number chosen is 3?


Answer:
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1/2
(Sorry I don't have the answer choices for the question above.)
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The following pairs are the options that yield an absolute difference of 2:

(1,3), (3,1), (2,4), (4,2), (3,5), (5,3), (4,6), (5,7)

There are 8 possible pairs to be selected, and 4 of them contain a 3, so the probability that one of the numbers chosen is 3 is 4/8 = 1/2.
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A set P = {1, 2, 3, 4, 5} and set Q = {1, 2, 3, 4, 5, 6, 7} Mon Jul 03, 2023 2:58 am
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