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| Last visit was: 24 Apr 2026, 11:16 |
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81% (02:12) correct
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| Now we will have two cases | |
| -Case 1: Q - 7 ≥ 0 => |Q -7 | = Q-7 => |Q - 7 +Q|=Q => | 2Q - 7| = Q Since Q - 7 ≥ 0 and Q ≥ 0 => 2Q - 7 ≥ 0 => | 2Q - 7| = 2Q - 7 => 2Q - 7 = Q => Q = 7 Which satisfies the condition of Q - 7 ≥ 0 and Q ≥ 0 => Q = 7 is a solution | -Case 2: Q - 7 ≤ 0 => |Q -7 | = -(Q-7) = -Q + 7 => |-Q + 7 +Q|=Q => |7| = Q => Q = 7 Which satisfies the condition of Q - 7 ≤ 0 and Q ≥ 0 => Q = 7 is a solution |
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