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Sub 505 (Easy)|   Roots|                        
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Bunuel
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Bunuel
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Bunuel
If \(n=\sqrt{\frac{16}{81}}\), what is the value of \(\sqrt{n}\)?

(A) 1/9
(B) 1/4
(C) 4/9
(D) 2/3
(E) 9/2

\(\sqrt{{\frac{16}{81}}}\)

Therefore n =\(\frac{4}{3}\)

and \(\sqrt{n}\) = \(\sqrt{{\frac{4}{9}}}\)

\(\frac{2}{3}\)

(D)
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Bunuel
If \(n=\sqrt{\frac{16}{81}}\), what is the value of \(\sqrt{n}\)?

(A) 1/9
(B) 1/4
(C) 4/9
(D) 2/3
(E) 9/2

Pretty straightforward question:
\(n=\sqrt{\frac{16}{81}} = \frac{4}{9}\)

\(\sqrt{n} = \sqrt{\frac{4}{9}} = \frac{2}{3} (D)\)
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Bunuel
If \(n=\sqrt{\frac{16}{81}}\), what is the value of \(\sqrt{n}\)?

(A) 1/9
(B) 1/4
(C) 4/9
(D) 2/3
(E) 9/2

Since n = √(16/81) = √16/√81 = 4/9, we see that √n = √(4/9) = √4/√9 = 2/3.

Answer: D
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n=√16/81

=>n=4/9

=>√n=√4/9 [√ both side]

=>√n=2/3

Answer is D ☺

Posted from my mobile device
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AkshdeepS
n = 4/9 NOT 4/3. I think you left a typo, but as it is a math, it can create confusion to new learners.
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No tricks here:

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I just did root 4*4 upon 9*9 and brought 2/3 outside and 2/3 remained inside and that is our answer, as it is simplified to the smallest form. Not sure it is right.
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Rishm It's better if you attach an image of your solution. However, it can be solved as below:

Since square root are always >=0.

Hence, n=(16/81)^1/2=4/9

now n^1/2=(4/9)^1/2=2/3

Hope this helps.
Rishm
I just did root 4*4 upon 9*9 and brought 2/3 outside and 2/3 remained inside and that is our answer, as it is simplified to the smallest form. Not sure it is right.
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Bunuel
If \(n=\sqrt{\frac{16}{81}}\), what is the value of \(\sqrt{n}\)?

(A) 1/9
(B) 1/4
(C) 4/9
(D) 2/3
(E) 9/2





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