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VandyonWheels
Joined: 16 Jul 2012
Last visit: 11 May 2013
Posts: 10
Given Kudos: 24
Location: India
Concentration: Sustainability, Leadership
Schools: Rotman '15 (A) Ross '15 (D)
GMAT 1: 690 Q44 V40
GPA: 3.6
WE:Design (Telecommunications)
Updated on: 17 Mar 2019, 03:18
Originally posted by VandyonWheels on 07 Nov 2012, 06:53.
Last edited by Bunuel on 17 Mar 2019, 03:18, edited 2 times in total.
Last edited by Bunuel on 17 Mar 2019, 03:18, edited 2 times in total.
Renamed the topic.
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
63% (01:50) correct
37%
(01:49)
wrong
based on 219
sessions
History
Date
Time
Result
Not Attempted Yet
In how many ways can 3 people out of 14 people be given 3 prizes(gold,silver,bronze) so that Jack is awarded? Jack is one of 14 people.
A) 2184
B) 546
C) 468
D) 364
E) 156
A) 2184
B) 546
C) 468
D) 364
E) 156
The given answer is 468
but I have not been able to understand how.
The direction that I proceeded was:
Jack gets gold or jack gets silver or jack gets bronze
=\(13*12 + 13*12 + 13*12\)
This seems to be wrong,so if somebody could explain where I'm going wrong and how to arrive at the correct answer it would be great!
Please help!
but I have not been able to understand how.
The direction that I proceeded was:
Jack gets gold or jack gets silver or jack gets bronze
=\(13*12 + 13*12 + 13*12\)
This seems to be wrong,so if somebody could explain where I'm going wrong and how to arrive at the correct answer it would be great!
Please help!
07 Nov 2012, 07:03
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Bookmarks
In how many ways can 3 people out of 14 people be given 3 prizes(gold,silver,bronze) so that Jack is awarded? Jack is one of 14 people.
The number of groups of 3 to receive prizes is \(C^2_{13}=78\).
Each of these groups of 3 can be arranged in 3!=6 ways, thus the total ways is 78*6=468.
P.S. Please read carefully and follow: rules-for-posting-please-read-this-before-posting-133935.html Please pay attention to the rules #2 and 8. Thank you.
The number of groups of 3 to receive prizes is \(C^2_{13}=78\).
Each of these groups of 3 can be arranged in 3!=6 ways, thus the total ways is 78*6=468.
P.S. Please read carefully and follow: rules-for-posting-please-read-this-before-posting-133935.html Please pay attention to the rules #2 and 8. Thank you.
General Discussion
aceon
Joined: 24 Apr 2011
Last visit: 17 Jul 2017
Posts: 12
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Given Kudos: 3
Location: United States
Schools: Duke '15 (WL) Booth '15 (D)
GMAT 1: 710 Q49 V39
GPA: 3.67
07 Nov 2012, 07:10
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Brunel,
I'm having difficulty understanding why you multiply by 3! Instead
Of simply 3.
Thank you.
Posted from my mobile device
I'm having difficulty understanding why you multiply by 3! Instead
Of simply 3.
Thank you.
Posted from my mobile device
