Jessica can text 85 words per minute, while Maurice can tex

Question

Jessica can text 85 words per minute, while Maurice can text 10 words per minute. An abridged English translation of Tolstoy’s War and Peace contains 410,400 words. Working together, how many days will it take Jessica and Maurice to text the entire abridged translation of War and Peace?

A .3
B 1.3
C 3
D 9
E 11.3

A. 0.3
B. 1.3
C. 3
D. 9
E. 11.3

BrentGMATPrepNow · Accepted Answer

Since the answer choices are somewhat spread apart, we can probably  use some estimation ...

Jessica can text 85 words per minute, while Maurice can text 10 words per minute  
So, COMBINED, they can text 95 words per minute
Let's round this up to  100  words per minute
So, the number of words PER HOUR = (100)(60) = 6000
And, the number of words PER DAY = (24)(6000) ≈ (25)(6000) ≈  150,000

So, COMBINED, the two people can text   approximately    150,000  words per day

Working together, how many days will it take Jessica and Maurice to text 410,400 words?  
Time = output/rate
= 410,400/ 150,000 
≈3

Answer: C

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BrushMyQuant · Answer

Given that Jessica can text 85 words per minute, while Maurice can text 10 words per minute. An abridged English translation of Tolstoy’s War and Peace contains 410,400 words. And we need to find Working together, how many days will it take Jessica and Maurice to text the entire abridged translation of War and Peace?

Rate of Jessica  = 85 words/min

Rate of Maurice  = 10 words/min

When they work together then their  Combined Rate = Rate of Jessica + Rate of Maurice  = 85 + 10 = 95words/min

Using,   Rate * Time = Work Done

=> 95 words/min * Time = 410,400 words

=> Time = 410,400/95 mins = 4,320mins = 4320/60 hours = 72hours = 72/24 days = 3 days

So,  Answer will be C 
Hope it helps!

Watch the following video to learn How to Solve Work Rate Problems

https://www.youtube.com/watch?v=dRxzi_x3ZwY

smvjkumar · Answer

Combined, they can text 95 words per minute.

So they will take 410,400 / 95 = 4320 mins to type the entire book

which is 4320/(60*24) days = 3 days

MacFauz · Answer

Since the answer choices are reasonably spaced out, we can approximate and save time

Combined words per day = 95*60*24 which should be something close to 150000 (i.e 100*25*60)

410400/150000 will be closest to only 3,

So, Answer should be C.

TGC · Answer

Rate * Time = Work

Combined Rate = 85+10

95*Time = 41400

Time in Days = 41400/(95*60*24)

T=3

The3hrd · Answer

I followed this question perfectly until I got to the 410400/95 part to get the total minutes it would take. Is there a math shortcut for this because fumbled with the long division along time

chetan2u · Answer

hi  gradyf ,

Not likely that you will see such intensive calculations..
But if you such a Q..

Combined speed 85+10=95 words/min..
so 410400 words in  \frac{410400}{95*60*24}  days..

Now see if choices can help you...
4104 is a multiple of 9 as 4+1+0+4 is multiple of 9.....
4104 is also a multiple of 19 as the Denominator 95 is a multiple of 19 and NONE of the choices have 19..
also 4104 is a multiple of 8 as LAST 3 digits 104 is multiple of 8....
when you multiply 9*19*8, you realize only another 3 is required to reach 4104...
so  \frac{19*9*8*3*100}{19*5*60*8*3}=\frac{9*10*5*2}{5*3*2*10}=3

ofcourse still calculations are there but slightly lesser work

JeffTargetTestPrep · Answer

Together they can text 85 + 10 = 95 words per minute, which means they can text 95 x 60 = 5,700 words per hour. Therefore, if we let x = the number of hours it takes for them to text the entire abridged translation of War and Peace, we have:

5,700x = 410,400

x = 410,400/5,700

x = 72 hours

Assuming they work 24 hours a day, it will take them 72/24 = 3 days to text the entire abridged translation of War and Peace.

Answer: C

Kinshook · Answer

Total words per minute = 85+10=95
Total words =410400
Time required = 410400/95 = 4320 minutes = 72 hours = 3 days

IMO C

Posted from my mobile device

mm229966 · Answer

Jessica's rate 85 w/m
Maurice's rate 10 w/m
Combined 95 words per minute;

410,400/95 = 4320 Minutes;
4320/(24*60)= 3 Days.

Pritishd · Answer

Combined rate of Maurice and Jessica is  10 + 85 = 95   \frac{words}{minute}

Rate = \frac{Work}{Time}

95 = \frac{410,400}{Time}

Time = \frac{410,400}{95} minutes

Converting into days:  \frac{410,400}{95}   minutes   *   \frac{1}{60}   \frac{hour}{minutes}   *   \frac{1}{24}   \frac{day}{hours}

The minutes and hours cancel out to give the number of days. Solving the expression yields,
3 days, Ans  C

minustark · Answer

Jessica and Maurice can text 95 words in 1 minute. To text the book together they need = 410,400/ 95*60 hour = 432/6 = 72 hour or 3 days.

C is the answer.

optimusprime07 · Answer

so every minute both can text 95 words and total words are 410400 words 
so total minutes required = 410400 / 95 
 = 4320 minutes 
now convert in days 
 4320 / ( 60* 24) = 3 days

daniformic · Answer

combined rate = 85 + 10 = 95 w/min
work = 410,400
time = 410,400/95m = 4320m = 4320m/60m = 72h = 72h/24d =  3days

Answer -> C

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Jessica can text 85 words per minute, while Maurice can tex

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