The ratio of the length to the width of a rectangular advert

Question

The ratio of the length to the width of a rectangular advertising display is approximately 3.3 to 2. If the width of the display is 8 meters, what is the approximate length of the display, in meters?

(A) 7
(B) 11
(C) 13
(D) 16
(E) 26

Bunuel · Answer

Given that  \frac{length}{width}=\frac{3.3}{2} . Since  width=8 , then  \frac{length}{8}=\frac{3.3}{2}  -->  length=8*\frac{3.3}{2}=13.2 .

Answer: C.

luckyme17187 · Answer

l:w
3.3:2

given width is 8 then 2 *4 ....

we have to do the same with L to find the right ratio.

3.3 * 4 approx 13

PareshGmat · Answer

Answer  = 3.3 * \frac{8}{2} = 13.2

Answer = C

kreel11 · Answer

ratio is 3.3:2 and width is 8 which means multiplier is 4 (2*4=8). Hence multiply length by 4 as well, instead of 3.3 take 3
so length is 3*4=12 since it is just over it the answer should be 13 (to check multiply 0.3*4=1.2 and add to 12)

SeregaP · Answer

we have ration l:w 3,3:2
and w is 8, then 8/2=4 
4*3,3=cca 13

matthewsmith_89 · Answer

My approach:

3.3 is the length
2 is the width

2/5.3 x a = 8
x = 8(5.3)/2
x = 21.2

3.3/5.3 x 21.2
3.3 x 4
13.2

Which is answer C

BrentGMATPrepNow · Answer

This is a matter of  EQUIVALENT RATIOS  
 length / width :  3.3 / 2  =  x / 8

Approach #1 
Notice that the width increases by a factor of 4 (from  2  to  8 )
So, the length must increase be a factor of 4 as well. 
 3.3 (4) = 13.2

Answer:  C

Approach #2 
 3.3 / 2  =  x / 8 
Cross multiply: (3.3)(8) = (2)(x)
Evaluate: 26.4 = 2x
Solve: x = 13.2

Answer:  C

RELATED VIDEO FROM OUR COURSE
 https://www.youtube.com/watch?v=Yegch7sv6MY

JeffTargetTestPrep · Answer

Let’s first set up our ratio using variable multipliers.
 
length : width = 3.3x : 2x
 
We are given that the width is 8 meters, so we set up the following equation:
 
2x = 8
 
x = 4
 
Thus, we know that the length is (4)(3.3) = 13.2 meters.
 
The closest answer is 13.
 
Answer: C

gupta335 · Answer

The ratio of the length to the width of a rectangular advertising display is approximately 3.3 to 2. If the width of the display is 8 meters, what is the approximate length of the display, in meters?

Let the length and the width be 3.3x and 2x respectivily.

Now, 2x=8

x=4

therefore, 3.3*4=13.2

Approx Value=13

Ans. C

Abhishek009 · Answer

Length =  3.3x  & Width =  2x

Now,  2x = 8

Or,  x = 4

So, Length  =3.3*4 = 13.20  , Answer must be (C)

hasnain3047 · Answer

length:width = 3.3:2
length=3.3x
width=2x
as
2x=8
x=4
so
length=3.3*4 =~13

totaltestprepNick · Answer

C https://www.youtube.com/watch?v=0zJfPFZFub4 Nick Slavkovich, GMAT/GRE tutor with 20+ years of experience tutoring@totaltestprep.net

The ratio of the length to the width of a rectangular advert

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The ratio of the length to the width of a rectangular advert

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