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Difficulty:
5%
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Question Stats:
94% (00:50) correct
6%
(01:13)
wrong
based on 2389
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The ratio of the length to the width of a rectangular advertising display is approximately 3.3 to 2. If the width of the display is 8 meters, what is the approximate length of the display, in meters?
(A) 7
(B) 11
(C) 13
(D) 16
(E) 26
(A) 7
(B) 11
(C) 13
(D) 16
(E) 26
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Walkabout
Given that \(\frac{length}{width}=\frac{3.3}{2}\). Since \(width=8\), then \(\frac{length}{8}=\frac{3.3}{2}\) --> \(length=8*\frac{3.3}{2}=13.2\).
Answer: C.
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Posts: 62
Walkabout
l:w
3.3:2
given width is 8 then 2 *4 ....
we have to do the same with L to find the right ratio.
3.3 * 4 approx 13
PareshGmat
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Last visit: 10 Jul 2016
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Answer \(= 3.3 * \frac{8}{2} = 13.2\)
Answer = C
Answer = C
ratio is 3.3:2 and width is 8 which means multiplier is 4 (2*4=8). Hence multiply length by 4 as well, instead of 3.3 take 3
so length is 3*4=12 since it is just over it the answer should be 13 (to check multiply 0.3*4=1.2 and add to 12)
so length is 3*4=12 since it is just over it the answer should be 13 (to check multiply 0.3*4=1.2 and add to 12)
we have ration l:w 3,3:2
and w is 8, then 8/2=4
4*3,3=cca 13
and w is 8, then 8/2=4
4*3,3=cca 13
Posts: 177
My approach:
3.3 is the length
2 is the width
2/5.3 x a = 8
x = 8(5.3)/2
x = 21.2
3.3/5.3 x 21.2
3.3 x 4
13.2
Which is answer C
3.3 is the length
2 is the width
2/5.3 x a = 8
x = 8(5.3)/2
x = 21.2
3.3/5.3 x 21.2
3.3 x 4
13.2
Which is answer C
Posts: 6,727
Walkabout
This is a matter of EQUIVALENT RATIOS
length/width: 3.3/2 = x/8
Approach #1
Notice that the width increases by a factor of 4 (from 2 to 8)
So, the length must increase be a factor of 4 as well.
3.3(4) = 13.2
Answer:
Approach #2
3.3/2 = x/8
Cross multiply: (3.3)(8) = (2)(x)
Evaluate: 26.4 = 2x
Solve: x = 13.2
Answer:
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Expert reply
Posts: 2,973
Walkabout
Let’s first set up our ratio using variable multipliers.
length : width = 3.3x : 2x
We are given that the width is 8 meters, so we set up the following equation:
2x = 8
x = 4
Thus, we know that the length is (4)(3.3) = 13.2 meters.
The closest answer is 13.
Answer: C
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The ratio of the length to the width of a rectangular advertising display is approximately 3.3 to 2. If the width of the display is 8 meters, what is the approximate length of the display, in meters?
Let the length and the width be 3.3x and 2x respectivily.
Now, 2x=8
x=4
therefore, 3.3*4=13.2
Approx Value=13
Ans. C
Let the length and the width be 3.3x and 2x respectivily.
Now, 2x=8
x=4
therefore, 3.3*4=13.2
Approx Value=13
Ans. C
Abhishek009
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Last visit: 17 Dec 2025
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Location: India
GPA: 3.5
WE:Business Development (Commercial Banking)
Posts: 5,880
Walkabout
Length = \(3.3x\) & Width = \(2x\)
Now, \(2x = 8\)
Or, \(x = 4\)
So, Length \(=3.3*4 = 13.20\) , Answer must be (C)
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Posts: 67
length:width = 3.3:2
length=3.3x
width=2x
as
2x=8
x=4
so
length=3.3*4 =~13
length=3.3x
width=2x
as
2x=8
x=4
so
length=3.3*4 =~13
GMAT 1: 750 Q49 V42
Posts: 469
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