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A dishonest person wants to make a profit on the selling of milk. He would like to mix water (costing nothing) with milk costing 33 $ per litre so as to make a profit of 20% on cost when he sells the resulting milk and water mixture for 36$. In what ratio should he mix the water and milk?
(A) 1:20
(B) 1:10
(C) 1:8
(D) 1:4
(E) 1:2
Dear guerrero25,
I'm happy to help with this. :-)

First of all, let's consider 1 liter of the stuff he is going to sell --- naive customers think it's pure milk, but we know it's some milk-water mixture. He is going to sell this liter of milk-water for $36.

This $36 should be a 20% increase over cost. Here, we need to think about percentage increases as multipliers. See this blog for more info:
https://magoosh.com/gmat/2012/understand ... -the-gmat/
Using multipliers
(cost)*1.20 = $36
cost = 36/1.2 = 360/12 = $30

If he wants a 20% increase over cost on the sale of one liter of his milk-water, the cost has to be $30.

Well, a liter of milk costs $33, so if he is going to use just $30 of milk in his mixture, that's 30/33 = 10/11 of a liter. If milk is 10/11 of the liter, then water is 1/11 of the liter, and the ratio of water to milk is 1:10. Answer choice (B)

Does all this make sense?
Mike :-)


Great solution, as always Mike! Thank you :)
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guerrero25
A dishonest person wants to make a profit on the selling of milk. He would like to mix water (costing nothing) with milk costing 33 $ per litre so as to make a profit of 20% on cost when he sells the resulting milk and water mixture for 36$. In what ratio should he mix the water and milk?
(A) 1:20
(B) 1:10
(C) 1:8
(D) 1:4
(E) 1:2
Dear guerrero25,
I'm happy to help with this. :-)

First of all, let's consider 1 liter of the stuff he is going to sell --- naive customers think it's pure milk, but we know it's some milk-water mixture. He is going to sell this liter of milk-water for $36.

This $36 should be a 20% increase over cost. Here, we need to think about percentage increases as multipliers. See this blog for more info:
https://magoosh.com/gmat/2012/understand ... -the-gmat/
Using multipliers
(cost)*1.20 = $36
cost = 36/1.2 = 360/12 = $30

If he wants a 20% increase over cost on the sale of one liter of his milk-water, the cost has to be $30.

Well, a liter of milk costs $33, so if he is going to use just $30 of milk in his mixture, that's 30/33 = 10/11 of a liter. If milk is 10/11 of the liter, then water is 1/11 of the liter, and the ratio of water to milk is 1:10. Answer choice (B)

Does all this make sense?
Mike :-)

Approached this question as follows -

He needs to make a profit of 20%, which means he needs to sell the milk +water combination for 39.6 (20% of 33 +33)
Now, he plans to sell 1 liter of this solution of milk and water for 36. which means he needs to sell 1.1 liters of this solution to earn 39.6. (36 for 1 liter and so 39.6 for 1.1 liters)

Hence the water added would be .1 liter.

Therefore the ratio of water to milk is .1/1 = 1/10

Please suggest if this approach is correct. Thanks
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guerrero25
A dishonest person wants to make a profit on the selling of milk. He would like to mix water (costing nothing) with milk costing 33 $ per litre so as to make a profit of 20% on cost when he sells the resulting milk and water mixture for 36$. In what ratio should he mix the water and milk?
(A)1:20
(B) 1:10
(C) 1:8
(D)1:4
(E)1:2

You can also use weighted averages.

Selling cost is $36 with profit of 20%.

Cost Price * 6/5 = $36
Cost Price = $30

Ww/Wm = (33 - 30)/(30 - 0) = 1/10 (Using weighted average formula discussed here: https://www.gmatclub.com/forum/veritas-prep-resource-links-no-longer-available-399979.html#/2011/03 ... -averages/)

Put 1 part water for every 10 parts of milk. Answer (B)
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guerrero25
A dishonest person wants to make a profit on the selling of milk. He would like to mix water (costing nothing) with milk costing 33 $ per litre so as to make a profit of 20% on cost when he sells the resulting milk and water mixture for 36$. In what ratio should he mix the water and milk?
(A) 1:20
(B) 1:10
(C) 1:8
(D) 1:4
(E) 1:2
Dear guerrero25,
I'm happy to help with this. :-)

First of all, let's consider 1 liter of the stuff he is going to sell --- naive customers think it's pure milk, but we know it's some milk-water mixture. He is going to sell this liter of milk-water for $36.

This $36 should be a 20% increase over cost. Here, we need to think about percentage increases as multipliers. See this blog for more info:
https://magoosh.com/gmat/2012/understand ... -the-gmat/
Using multipliers
(cost)*1.20 = $36
cost = 36/1.2 = 360/12 = $30

If he wants a 20% increase over cost on the sale of one liter of his milk-water, the cost has to be $30.

Well, a liter of milk costs $33, so if he is going to use just $30 of milk in his mixture, that's 30/33 = 10/11 of a liter. If milk is 10/11 of the liter, then water is 1/11 of the liter, and the ratio of water to milk is 1:10. Answer choice (B)

Does all this make sense?
Mike :-)

Assume M milk quantity and W water quantity in liters

Let's assume x= 33*(M/(M+W))+0*(W/M+W))= 33 (M/(M+W)) X EQUALS the weighted average of the prices with weights on the quantities

We know that the seller must make 20% of profit over cost by selling the mixture at 36$.
Thus (36-X)/X=0,20
(36-x)/X=20/100
X=30

Thus X=30= 33(M/(M+V)) and we get M/ M+W = 10/11

Thus for each 10/11 of milk we have 1/11 of water, thus their ratio must be 1:10.
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Hi Mike, can you help with the logic of my answer.

Water and Milk cost $33. Total cost is 33 (all milk) water costs nothing.

He wants to make 20% profit on his total cost. 33x1.2= 39.6. 3.6 of the profit would have to come from water?

The customer is assuming that he's selling pure milk at 36, but there's actually 3.6 worth of water in the mixture.

3.6/36 = 1/10

mikemcgarry

Dear guerrero25,
I'm happy to help with this. :-)

First of all, let's consider 1 liter of the stuff he is going to sell --- naive customers think it's pure milk, but we know it's some milk-water mixture. He is going to sell this liter of milk-water for $36.

This $36 should be a 20% increase over cost. Here, we need to think about percentage increases as multipliers. See this blog for more info:
https://magoosh.com/gmat/2012/understan ... -the-gmat/
Using multipliers
(cost)*1.20 = $36
cost = 36/1.2 = 360/12 = $30

If he wants a 20% increase over cost on the sale of one liter of his milk-water, the cost has to be $30.

Well, a liter of milk costs $33, so if he is going to use just $30 of milk in his mixture, that's 30/33 = 10/11 of a liter. If milk is 10/11 of the liter, then water is 1/11 of the liter, and the ratio of water to milk is 1:10. Answer choice (B)

Does all this make sense?
Mike :-)
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Fisayofalana
Hi Mike, can you help with the logic of my answer.

Water and Milk cost $33. Total cost is 33 (all milk) water costs nothing.

He wants to make 20% profit on his total cost. 33x1.2= 39.6. 3.6 of the profit would have to come from water?

The customer is assuming that he's selling pure milk at 36, but there's actually 3.6 worth of water in the mixture.

3.6/36 = 1/10


The $36 selling price is already fixed. The mixture must cost $30, not $33, because $30 with 20 percent profit becomes $36. So the mixture isn’t “$33 worth of milk minus 3.6 of water.”

If the mixture must cost $30 per liter and pure milk costs $33 per liter, you can only put in $30 dollars’ worth of milk. That is 30/33 of the liter. The rest of the liter is water.
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