th23autolink_encode_start_318yq1msW3VybD1odHRwcyYjNTg7Ly9nbWF0Y2x1YiYjNDY7Y29tJiM1ODs0NDMvZm9ydW0vbWVtYmVybGlzdCYjNDY7cGhwP21vZGU9dmlld3Byb2ZpbGUmYW1wO3VuPVZlcml0YXNQcmVwS2FyaXNobWE6MzE4eXExbXNdIHRoMjNhdXRvbGlua19iYmNvZGVfc3RhcnRfYl8zMTh5cTFtcyBWZXJpdGFzUHJlcEthcmlzaG1hIHRoMjNhdXRvbGlua19iYmNvZGVfZW5kX2JfMzE4eXExbXMgWy91cmw6MzE4eXExbXNdth23autolink_encode_end_318yq1ms wrote:
Responding to a pm:
A man cheats while buying as well as while selling. While buying he takes 10% more than what he pays for and while selling he gives 20% less than what he claims to. Find the profit percent, if he sells at 9.09% below the cost price of the claimed weight.
Options:
A. 19.81%
B. 20%
C. 37.5%
D. 25%
E. 37.5%
In weight questions, try to go one step at a time.
Say the man buys 100 pounds for $100. But he cheats and takes 110 pounds. This means HIS cost price is $10/11 per pound.
While giving 100 pounds, he actually gives only 80 pounds and charges 9.09% less i.e. 1/11 less than the cost price of 100 pounds which is $100. So he sells at 10/11 * 100 = 1000/11
HIS cost price for 80 pounds = 10/11 * 80 = 800/11
HIS selling price for 80 pounds = 1000/11
Profit = (1000/11 - 800/11)/800/11 * 100 = 25%
Hi
VeritasPrepKarishma ,
As I have understood , you got the man's REAL cost price i.e 10/11 per pound .
His Cost price for 80 kgs = 80 * 10/11
But his selling price for 80ks = 100 * 10/11 ( because he says its not 80 its hundred) .
And then you have calculated the difference . Where does the 9.09% factor in ?
shouldnt his selling price be = 100*10/11 - 9.09% [ 100*10/11] . which is not 100*10/11 . therefore changing the answer.
I spent quite a lot of time to understand this, any help will be appreciated.