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b2bt
A can complete a certain job in 12 days. B is 60% more efficient than A. In how many days can B complete the same job?

(A) 6
(B) 6.25
(C) 7
(D) 7.5
(E) 4.8

Kudos if you like the question..

Little awkward explanation.60% more efficient means B can do 160% of work in same no. of days as A takes to do 100% of work.
160% work in 12 days
100% work in x days
x = \(\frac{(12*100)}{160}\)

Set up a Rate Time Work Table and plug in the values:

Rate / Time / Work for A:
12 / 12 / 144

Rate / Time / Work for B:
19.2 / 7.5 / 144

Do not fall into the trap by just working with the time, i.e. taking 60% off from 12 days and subtracting it from 12. Trap Answer E.
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Let the number of units of work done by A in one day = 10, so B does 16 units of work per day.

Total units of work done by A = 12*10 = 120 units.

No. of days taken by B to do 120 units of work = 120/16 = 7.5. Ans (D).
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You could even do process elimination

let's start with C

7 x 1 3/5
56/5 or 11 1/5 Not the answer. Let's use a big number

D - 7 1/2 x 1 3/5
15/2 x 8/5
12

The answer is D
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b2bt
A can complete a certain job in 12 days. B is 60% more efficient than A. In how many days can B complete the same job?

(A) 6
(B) 6.25
(C) 7
(D) 7.5
(E) 4.8

The rate of A is 1/12.

Since B is 60% more efficient the rate of B is 1.6 x 1/12 = 1.6/12 = 16/120 = 2/15.

Since time is inverse of rate, B can complete the job in 15/2 = 7.5 days.

Answer: D
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b2bt
A can complete a certain job in 12 days. B is 60% more efficient than A. In how many days can B complete the same job?

(A) 6
(B) 6.25
(C) 7
(D) 7.5
(E) 4.8


Little awkward explanation.60% more efficient means B can do 160% of work in same no. of days as A takes to do 100% of work.
160% work in 12 days
100% work in x days
x = \(\frac{(12*100)}{160}\)

Hello there

This is a good Problem Solving question testing concept of Work-time.

Per given information,
Work done by A in 1 day
\(= \frac{1}{12}\)

Because B is 60% more efficient,
Work done by B
\(= 1.6 x \frac{1}{12}\)

Thus, time taken by B to complete the work
\(= \frac{12}{1.6}\)
= 7.5 days

Answer (D)

Is there anything I could clarify better in this solution? Pls share your thoughts.
Thank you. :)
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Let A do 10 units of work every day.
Since B is 60% more efficient than A, B will do 16 units of work per day.

Also, as A can complete the work in 12 days, total work = 12*10 = 120 days.

Time taken by B to complete the same work = 120/16 = 7.5 days.

Thus, the correct answer is D.
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Given: A can complete a certain job in 12 days. B is 60% more efficient than A.
Asked: In how many days can B complete the same job?

B is 1.6 times as efficient as A.
B will take = 12/1.6 = 30/4 = 7.5 days to complete the same job.

IMO D
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b2bt
A can complete a certain job in 12 days. B is 60% more efficient than A. In how many days can B complete the same job?

(A) 6
(B) 6.25
(C) 7
(D) 7.5
(E) 4.8


Little awkward explanation.60% more efficient means B can do 160% of work in same no. of days as A takes to do 100% of work.
160% work in 12 days
100% work in x days
x = \(\frac{(12*100)}{160}\)

Is it incorrect to add 60% of 12 to get 7.2, which is ~closest to the answer 7.5?
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b2bt
A can complete a certain job in 12 days. B is 60% more efficient than A. In how many days can B complete the same job?

(A) 6
(B) 6.25
(C) 7
(D) 7.5
(E) 4.8


Little awkward explanation.60% more efficient means B can do 160% of work in same no. of days as A takes to do 100% of work.
160% work in 12 days
100% work in x days
x = \(\frac{(12*100)}{160}\)

The question can be solved quickly using percentages and ratios.

Rate of B is 60% more than rate of A which means that rate of B is 8/5 the rate of A. So ratio of their rates is 8:5.

Then ratio of time taken by B:A will be 5:8.

Since A takes 12 days, 8 on ratio scale is equal to 12 actually so multiplier is 12/8 = 3/2.
Time. taken by B will be 5 * 3/2 = 7.5 days

Answer (D)

Check the following videos for more on
Ratios: https://youtu.be/5ODENGG5dvc
Percentages: https://youtu.be/HxnsYI1Rws8
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