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NickHalden
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Updated on: 06 Sep 2014, 00:28
Originally posted by NickHalden on 06 Sep 2014, 00:09.
Last edited by Gnpth on 06 Sep 2014, 00:28, edited 1 time in total.
Last edited by Gnpth on 06 Sep 2014, 00:28, edited 1 time in total.
Edited the topic
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
33% (01:54) correct
67%
(01:39)
wrong
based on 168
sessions
History
Date
Time
Result
Not Attempted Yet
How many 3 letter (not necessarily distinct) words can be formed using the letters from the word TWIST ?
A. 33
B. 54
C. 45
D. 60
E. None of the above
A. 33
B. 54
C. 45
D. 60
E. None of the above
06 Sep 2014, 12:00
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abhishekmishra87
Let's consider two cases:
1) Only one T is used
In this case the total possibilities are \(4! = 24\) as we need to select \(3\) letters and we can select any one out of the \(4\) (T, W, I, S) for the first one, any one out of the remaining \(3\) for the second and any one of the remaining \(2\) for the last one. The sample space is reduced to \(4\) as the two T's are indistinguishable.
This could also have been done as \(4P3 = \frac{4!}{{(4-3)!}} = 24\) (Permutation because the order matters)
2) Two T's are used
In this case we have to select just one letter out of the remaining \(3\) (W, I, S) which can be arranges in 3 places.
So, the total possibilities are \(3 * 3 = 9\)
Total possibilities \(24 + 9 = 33\)
So, the answer is A.
Hope that helps.
General Discussion
13 Oct 2014, 03:55
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Anamika2014
The question isn't well made. It states "not necessarily distinct", but the answer doesn't take account of arrangements in which 2 letters are the same, the 3rd is different and 3 letters are the same. For example IIT, WWI, WWW, etc.
