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Hi All

nachobioteck has already pointed out how easily this question can be solved by TESTing THE ANSWERS. There are a couple of 'shortcuts' worth noting about this prompt that can help you to solve it with this method in the most efficient way possible:

1) Based on the picture and the answer choices, the side lengths are all INTEGERS
2) There are only a handful of Pythagorean 'triplets' that the GMAT will/might test you on. The 3/4/5 and 5/12/13 (and multiples of those triangles) should come to mind.

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Bunuel
Attachment:
righttrianglealgebra_figure.PNG
What is the value of x?

A. 2
B. 3
C. 4
D. 5
E. 6

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I initially saw that we could use pythagorean theorem, but that seemed way too long. I did exactly what Rich mentioned, I started plugging in numbers. 3 looks good as it gives us a 5-12-13 triangle.

Answer: B
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Answer = B = 3

Modified the figure as shown below:

Attachment:
righttrianglealgebra_figure.PNG
righttrianglealgebra_figure.PNG [ 3.49 KiB | Viewed 5526 times ]

For x = 2, values 4, 9 & 11 are not Pythagoras triplet

For x = 3, values 5, 12 & 13 form it
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Bunuel

What is the value of x?

A. 2
B. 3
C. 4
D. 5
E. 6

Kudos for a correct solution.

MAGOOSH OFFICIAL SOLUTION:
Attachment:
righttrianglealgebra_text.PNG
righttrianglealgebra_text.PNG [ 14.63 KiB | Viewed 5498 times ]
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Attachment:
righttrianglealgebra_figure.PNG
What is the value of x?

A. 2
B. 3
C. 4
D. 5
E. 6

Kudos for a correct solution.


I solved with working the options approach. As they say, always keep an eye on the option in a PS problem.

Right angle Triangle, so pythagoras theorem:
\((2x+7)^2 = (x+2)^2 + (3x+3)^2\)

Now working with options:
a.\(x= 2, gave me: 121 = 16 + 81\)
NO.

b. \(x=3, 169 = 25+144.\)
Boom. Got it.

Quickly checked with other options to confirm that x =3 only fits and option B is the answer.
Thank you.
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Just saying - wish people would have read my entire answer.

I very obviously give a second approach of just plugging in the answers.
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